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The equation of the line having normal distance 2a from the origin and angle 60° which the normal makes with the positive direction of X-axis is:a)x +√2y = 5ab)x +√3y = 4ac)x + 4y +5 = 0d)x + 2y = 3aCorrect answer is option 'B'. Can you explain this answer? for JEE 2026 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about The equation of the line having normal distance 2a from the origin and angle 60° which the normal makes with the positive direction of X-axis is:a)x +√2y = 5ab)x +√3y = 4ac)x + 4y +5 = 0d)x + 2y = 3aCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for JEE 2026 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The equation of the line having normal distance 2a from the origin and angle 60° which the normal makes with the positive direction of X-axis is:a)x +√2y = 5ab)x +√3y = 4ac)x + 4y +5 = 0d)x + 2y = 3aCorrect answer is option 'B'. Can you explain this answer?.

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