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If at 298 K the bond energies of C–H, C–C, C=C and H–H bonds are respectively 414, 347, 615 and 435 kJ mol-1, the value of enthalpy change for the reaction ;H2C = CH2(g) + H2(g) →H3C–CH3(g) at 298 K will be – [aieee-2003]a)+125 kJb)-125 kJc)+250 kJd)- 250 kJCorrect answer is option 'B'. Can you explain this answer? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about If at 298 K the bond energies of C–H, C–C, C=C and H–H bonds are respectively 414, 347, 615 and 435 kJ mol-1, the value of enthalpy change for the reaction ;H2C = CH2(g) + H2(g) →H3C–CH3(g) at 298 K will be – [aieee-2003]a)+125 kJb)-125 kJc)+250 kJd)- 250 kJCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for If at 298 K the bond energies of C–H, C–C, C=C and H–H bonds are respectively 414, 347, 615 and 435 kJ mol-1, the value of enthalpy change for the reaction ;H2C = CH2(g) + H2(g) →H3C–CH3(g) at 298 K will be – [aieee-2003]a)+125 kJb)-125 kJc)+250 kJd)- 250 kJCorrect answer is option 'B'. Can you explain this answer?.

Solutions for If at 298 K the bond energies of C–H, C–C, C=C and H–H bonds are respectively 414, 347, 615 and 435 kJ mol-1, the value of enthalpy change for the reaction ;H2C = CH2(g) + H2(g) →H3C–CH3(g) at 298 K will be – [aieee-2003]a)+125 kJb)-125 kJc)+250 kJd)- 250 kJCorrect answer is option 'B'. Can you explain this answer? in English & in Hindi are available as part of our courses for Class 11. Download more important topics, notes, lectures and mock test series for Class 11 Exam by signing up for free.

Here you can find the meaning of If at 298 K the bond energies of C–H, C–C, C=C and H–H bonds are respectively 414, 347, 615 and 435 kJ mol-1, the value of enthalpy change for the reaction ;H2C = CH2(g) + H2(g) →H3C–CH3(g) at 298 K will be – [aieee-2003]a)+125 kJb)-125 kJc)+250 kJd)- 250 kJCorrect answer is option 'B'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of If at 298 K the bond energies of C–H, C–C, C=C and H–H bonds are respectively 414, 347, 615 and 435 kJ mol-1, the value of enthalpy change for the reaction ;H2C = CH2(g) + H2(g) →H3C–CH3(g) at 298 K will be – [aieee-2003]a)+125 kJb)-125 kJc)+250 kJd)- 250 kJCorrect answer is option 'B'. Can you explain this answer?, a detailed solution for If at 298 K the bond energies of C–H, C–C, C=C and H–H bonds are respectively 414, 347, 615 and 435 kJ mol-1, the value of enthalpy change for the reaction ;H2C = CH2(g) + H2(g) →H3C–CH3(g) at 298 K will be – [aieee-2003]a)+125 kJb)-125 kJc)+250 kJd)- 250 kJCorrect answer is option 'B'. Can you explain this answer? has been provided alongside types of If at 298 K the bond energies of C–H, C–C, C=C and H–H bonds are respectively 414, 347, 615 and 435 kJ mol-1, the value of enthalpy change for the reaction ;H2C = CH2(g) + H2(g) →H3C–CH3(g) at 298 K will be – [aieee-2003]a)+125 kJb)-125 kJc)+250 kJd)- 250 kJCorrect answer is option 'B'. Can you explain this answer? theory, EduRev gives you an ample number of questions to practice If at 298 K the bond energies of C–H, C–C, C=C and H–H bonds are respectively 414, 347, 615 and 435 kJ mol-1, the value of enthalpy change for the reaction ;H2C = CH2(g) + H2(g) →H3C–CH3(g) at 298 K will be – [aieee-2003]a)+125 kJb)-125 kJc)+250 kJd)- 250 kJCorrect answer is option 'B'. Can you explain this answer? tests, examples and also practice Class 11 tests.