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Suppose you are given an implementation of a queue of integers. The operations that can be performed on the queue are:
i. isEmpty (Q) — returns true if the queue is empty, false otherwise.
ii. delete (Q) — deletes the element at the front of the queue and returns its value.
iii. insert (Q, i) — inserts the integer i at the rear of the queue.
Consider the following function:
void f (queue Q) {
int i ;
if (!isEmpty(Q)) {
 i = delete(Q);
f(Q);
insert(Q, i);
}
}
What operation is performed by the above function f ?
  • a)
    Leaves the queue Q unchanged
  • b)
    Reverses the order of the elements in the queue Q
  • c)
    Deletes the element at the front of the queue Q and inserts it at the rear keeping the other elements in the same order
  • d)
    Empties the queue Q
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
Suppose you are given an implementation of a queue of integers. The op...
insert() will inserts the value in just reverse order.
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Most Upvoted Answer
Suppose you are given an implementation of a queue of integers. The op...
Explanation:

The given function f is a recursive function that reverses the order of elements in the queue Q. Let's understand how.

Algorithm:

1. Check if the queue is not empty.
2. If it is not empty, delete the element at the front of the queue and store its value in the variable i.
3. Call the function f(Q) recursively.
4. Insert the value of i at the rear of the queue.

Let's consider an example to understand this algorithm.

Example:

Suppose we have a queue Q = {1, 2, 3, 4}. Now let's apply the function f(Q) on this queue.

Step 1: Check if the queue is not empty. Since the queue is not empty, move to step 2.

Step 2: Delete the element at the front of the queue and store its value in the variable i. So, i = 1 and Q = {2, 3, 4}.

Step 3: Call the function f(Q) recursively. Now, the function f(Q) is called with Q = {2, 3, 4}.

Step 4: Repeat steps 1 to 3. The function f(Q) is called again with Q = {3, 4}. i = 2, Q = {3, 4, 1}. The function f(Q) is called again with Q = {4}. i = 3, Q = {4, 1, 2}. The function f(Q) is called again with Q = {}. Since the queue is empty, the function returns.

Step 5: Insert the value of i at the rear of the queue. In the first call, i = 1 is inserted at the rear of the queue. In the second call, i = 2 is inserted at the rear of the queue. In the third call, i = 3 is inserted at the rear of the queue. In the final call, there is nothing to insert.

Step 6: The final queue is Q = {4, 3, 2, 1}. This is the reverse of the original queue Q = {1, 2, 3, 4}.

Conclusion:

Hence, we can conclude that the given function f is a recursive function that reverses the order of elements in the queue Q.
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Community Answer
Suppose you are given an implementation of a queue of integers. The op...
Here, we delete elements from the queue till it becomes empty and after that we insert the last deleted element at the rear end of the queue. The recursive calls would eventually unwind to give all the elements in the reverse order.
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Suppose you are given an implementation of a queue of integers. The operations that can be performed on the queue are:i. isEmpty (Q) — returns true if the queue is empty, false otherwise.ii. delete (Q) — deletes the element at the front of the queue and returns its value.iii. insert (Q, i) — inserts the integer i at the rear of the queue.Consider the following function:void f (queue Q) {int i ;if (!isEmpty(Q)) {i = delete(Q);f(Q);insert(Q, i);}}What operation is performed by the above function f ?a)Leaves the queue Q unchangedb)Reverses the order of the elements in the queue Qc)Deletes the element at the front of the queue Q and inserts it at the rear keeping the other elements in the same orderd)Empties the queue QCorrect answer is option 'B'. Can you explain this answer?
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