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5.6 L of a gas at NTP weight 8g . What is it moleculer mass?
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5.6 L of a gas at NTP weight 8g . What is it moleculer mass?
Molar mass can be found as:

Mass of one mole of gas = Molar mass of the gas

1 mole of gas at STP = 22.4 L.

5.6 L of gas = 8 g

22.4 L o f gas = (22.4x8) / 5.6 = 32 g

Thus, Mass of one mole of gas = 32 g.

So, molar mass of the gas = 32 g/mol
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5.6 L of a gas at NTP weight 8g . What is it moleculer mass?
Calculation of Molar Mass of Gas

Given Data:
- Volume of gas (V) = 5.6 L
- Pressure (P) = 1 atm
- Temperature (T) = 273 K (NTP)
- Weight of gas = 8g

Step 1: Calculate moles of gas using Ideal Gas Law
- PV = nRT
- n = PV/RT
- n = (1 atm * 5.6 L) / (0.0821 atm L/mol K * 273 K)
- n = 0.244 moles

Step 2: Calculate molar mass
- Molar mass = Weight / moles
- Molar mass = 8g / 0.244 mol
- Molar mass = 32.79 g/mol

Explanation:
- To calculate the molar mass of the gas, we first use the Ideal Gas Law to find the number of moles of the gas present in the given volume at NTP.
- Once we have the number of moles, we can then determine the molar mass by dividing the weight of the gas by the number of moles.
- In this case, the molar mass of the gas is calculated to be 32.79 g/mol.
This process helps in determining the molecular mass of the gas based on its weight and volume at standard conditions.
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5.6 L of a gas at NTP weight 8g . What is it moleculer mass?
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