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6) a motorist drives north for 35.0 minutes at 85.0 km per hour and then stops for 15.0 minutes, he next continues north, travelling 130 km in 2 hours. what is his total displacement?Sol) 179.6 kmph?
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6) a motorist drives north for 35.0 minutes at 85.0 km per hour and th...
Total displacement: 
179.6 km

Average velocity: 
63.4 km/h

Since it's travelling in the same direction for the entire duration of its journey, the total displacement of the car is simply the distance from the starting point.

In the first part of its journey, the car travelled for 35 minutes at a speed of 85 km/h. Convert the time from minutes to hours to get

35min ⋅ 1h/60min = 0.5833 h

This means that the car covered

0.5833 h ⋅ 85 k/1h = 49.6 km

The car stops, then continues along its current direction, covering 130 km in 2 hours. The total displacement of the car will thus be

dtotal = 49.6 + 130 = 179.6 km

The average velocity is simply the total dispalcement divided by the total time of travel. In your case, the total time will be
ttotal

=0.5833 h + 0.25 h + 2h = 2.833 h = 15 min

The average velocity is

vector (v) = 179.6 km/2.833h = 63.4 km/h
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6) a motorist drives north for 35.0 minutes at 85.0 km per hour and th...
Problem:
A motorist drives north for 35.0 minutes at 85.0 km per hour and then stops for 15.0 minutes. He next continues north, traveling 130 km in 2 hours. What is his total displacement?

Solution:

To find the total displacement of the motorist, we need to consider both his initial movement and his subsequent movement.

Initial Movement:
The motorist drives north for 35.0 minutes at a speed of 85.0 km per hour. To find the distance covered, we can use the formula:

Distance = Speed × Time

Distance = 85.0 km/h × (35.0 minutes ÷ 60 minutes/hour) = 85.0 km/h × 0.5833 hour = 49.6 km

The motorist's initial movement covers a distance of 49.6 km in the north direction.

Subsequent Movement:
After the initial movement, the motorist stops for 15.0 minutes. Therefore, the time taken for the subsequent movement is 2 hours - 15.0 minutes = 1.75 hours.

The motorist travels 130 km during this subsequent movement.

Total Displacement:
Total displacement is the net vector sum of all the individual displacements. In this case, since the motorist is moving only in the north direction, the total displacement is the sum of the distances covered in both the initial and subsequent movements.

Total displacement = Distance (Initial Movement) + Distance (Subsequent Movement)
Total displacement = 49.6 km + 130 km = 179.6 km

Therefore, the motorist's total displacement is 179.6 km north.

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6) a motorist drives north for 35.0 minutes at 85.0 km per hour and then stops for 15.0 minutes, he next continues north, travelling 130 km in 2 hours. what is his total displacement?Sol) 179.6 kmph?
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6) a motorist drives north for 35.0 minutes at 85.0 km per hour and then stops for 15.0 minutes, he next continues north, travelling 130 km in 2 hours. what is his total displacement?Sol) 179.6 kmph? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about 6) a motorist drives north for 35.0 minutes at 85.0 km per hour and then stops for 15.0 minutes, he next continues north, travelling 130 km in 2 hours. what is his total displacement?Sol) 179.6 kmph? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for 6) a motorist drives north for 35.0 minutes at 85.0 km per hour and then stops for 15.0 minutes, he next continues north, travelling 130 km in 2 hours. what is his total displacement?Sol) 179.6 kmph?.
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