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A straight conductor carrying current I is split into circular loop as shown in figure a , the magnetic induction at the center of the circular loop is
  • a)
    Zero
  • b)
  • c)
  • d)
    Infinite
Correct answer is option 'A'. Can you explain this answer?
Verified Answer
A straight conductor carrying current I is split into circular loop as...
The magnetic field at the center O due to the upper side of the semicircular current loop is equal and opposite to that due to the lower side of the loop.

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Most Upvoted Answer
A straight conductor carrying current I is split into circular loop as...
Because the direction of the magnetic field is opposite i.e. in upper arc it is inward and in lower arc it is outward
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Community Answer
A straight conductor carrying current I is split into circular loop as...
 
The magnetic field at the center O due to the upper side of the semicircular current loop is equal and opposite to that due to the lower side of the loop.
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A straight conductor carrying current I is split into circular loop as shown in figure a , the magnetic induction at the center of the circular loop isa)Zerob)c)d)InfiniteCorrect answer is option 'A'. Can you explain this answer?
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A straight conductor carrying current I is split into circular loop as shown in figure a , the magnetic induction at the center of the circular loop isa)Zerob)c)d)InfiniteCorrect answer is option 'A'. Can you explain this answer? for Class 12 2024 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about A straight conductor carrying current I is split into circular loop as shown in figure a , the magnetic induction at the center of the circular loop isa)Zerob)c)d)InfiniteCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for Class 12 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A straight conductor carrying current I is split into circular loop as shown in figure a , the magnetic induction at the center of the circular loop isa)Zerob)c)d)InfiniteCorrect answer is option 'A'. Can you explain this answer?.
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