One Integer Value Correct TypeThis section contains 3 questions, when ...
Solution:
Given,
- Atoms of element B form hep lattice
- Atoms of element A occupy 2/3rd of tetrahedral voids
To find:
- Total number of atoms of A and B in the hep lattice
Let's assume that there are 'x' atoms of B and 'y' atoms of A in the hep lattice.
Number of tetrahedral voids = Number of atoms of B
Number of octahedral voids = Number of atoms of A/2
As per the question, atoms of A occupy 2/3rd of tetrahedral voids.
Therefore, number of atoms of A in tetrahedral voids = 2/3 * Number of atoms of B
Also, number of atoms of A in octahedral voids = Number of atoms of A/2
Total number of atoms of A = Number of atoms of A in tetrahedral voids + Number of atoms of A in octahedral voids
= 2/3 * Number of atoms of B + Number of atoms of A/2
= 4/6 * Number of atoms of B + 3/6 * Number of atoms of A
= (4/6)x + (3/6)y
Similarly, total number of atoms of B = x
Total number of atoms in the hep lattice = x + [(4/6)x + (3/6)y]
= (10/6)x + (3/6)y
= (5/3)x + (1/2)y
As the total number of atoms in the hep lattice is an integer value, we can assume that x = 3.
Substituting x = 3 in the above equation, we get:
Total number of atoms in the hep lattice = (5/3)(3) + (1/2)y
= 5 + (1/2)y
For the total number of atoms in the hep lattice to be an integer, y must be odd.
Therefore, possible values of y are 1, 3, 5, 7, and 9.
Out of these, only for y=7, the total number of atoms in the hep lattice will be an integer.
Hence, the correct answer is '7'.
One Integer Value Correct TypeThis section contains 3 questions, when ...
Number of atoms in tetrahedral in small cube of unit cell of B = 4
Thus, tetrahedral voids in unit cell of B = 8.
Number of atoms of A = 2/3 of tetrahedral voids of B
Total number of atoms in lattice = 4 + 3 = 7