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A 650 ml solution has 25% alcohol. How much alcohol must be mixed with the solution so that the resultant mixture has 35% alcohol?
  • a)
    50 ml
  • b)
    75 ml
  • c)
    100 ml
  • d)
    150 ml
Correct answer is option 'C'. Can you explain this answer?
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Understanding the Problem
To solve the problem, we need to determine how much alcohol must be added to a 650 ml solution that has 25% alcohol to achieve a final concentration of 35%.
Initial Alcohol Content
- The initial solution has a volume of 650 ml.
- The concentration of alcohol is 25%.
Calculating the initial amount of alcohol:
- Initial amount of alcohol = 25% of 650 ml
- Initial amount of alcohol = 0.25 * 650 = 162.5 ml
Final Concentration Requirement
- Let "x" be the amount of alcohol to be added.
- After adding x ml of alcohol, the total volume of the solution becomes (650 + x) ml.
- The new alcohol content will be (162.5 + x) ml.
We want the final solution to have a concentration of 35%, so we set up the equation:
- (162.5 + x) / (650 + x) = 35%
Solve the Equation
1. Cross-multiply to eliminate the fraction:
- 162.5 + x = 0.35 * (650 + x)
2. Distributing:
- 162.5 + x = 227.5 + 0.35x
3. Rearranging:
- 162.5 + x - 0.35x = 227.5
- 0.65x = 227.5 - 162.5
- 0.65x = 65
4. Solving for x:
- x = 65 / 0.65
- x = 100 ml
Conclusion
To achieve a 35% alcohol concentration, you need to add 100 ml of alcohol to the original solution. Thus, the correct answer is option C.
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Question Description
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