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R1= (6±0.2)Ω and R2 = (8±0.6). 1) find total resistance if it is connected in parallel. 2) maximum %age error in resistance?
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R1= (6±0.2)Ω and R2 = (8±0.6). 1) find total resistance if it is conne...
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R1= (6±0.2)Ω and R2 = (8±0.6). 1) find total resistance if it is conne...
1) Calculation of total resistance:

When resistors are connected in parallel, the total resistance (Rt) can be calculated using the formula:

1/Rt = 1/R1 + 1/R2 + ...

In this case, R1 = (6±0.2)Ω and R2 = (8±0.6)Ω. To calculate the total resistance, we need to substitute the values of R1 and R2 into the formula.

1/Rt = 1/(6±0.2) + 1/(8±0.6)

To find the total resistance, we need to consider the maximum and minimum values of R1 and R2.

Using the maximum values:

1/Rt_max = 1/(6+0.2) + 1/(8+0.6)
= 1/6.2 + 1/8.6

Simplifying,

1/Rt_max = 0.161 + 0.116
= 0.277

Taking the reciprocal on both sides,

Rt_max = 1/0.277
≈ 3.61Ω

Using the minimum values:

1/Rt_min = 1/(6-0.2) + 1/(8-0.6)
= 1/5.8 + 1/7.4

Simplifying,

1/Rt_min = 0.172 + 0.135
= 0.307

Taking the reciprocal on both sides,

Rt_min = 1/0.307
≈ 3.26Ω

Therefore, the total resistance (Rt) when the resistors are connected in parallel is approximately 3.26Ω to 3.61Ω.

2) Calculation of maximum percentage error in resistance:

To calculate the maximum percentage error in resistance, we need to use the formula:

% error = (Max value - Min value) / Average value * 100

In this case, we have the maximum and minimum values of the total resistance, which are 3.61Ω and 3.26Ω, respectively. To calculate the average value, we can use the formula:

Average value = (Max value + Min value) / 2

Average value = (3.61 + 3.26) / 2
= 3.435Ω

Substituting the values into the formula:

% error = (3.61 - 3.26) / 3.435 * 100
= 0.35 / 3.435 * 100
≈ 10.19%

Therefore, the maximum percentage error in resistance is approximately 10.19%.
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R1= (6±0.2)Ω and R2 = (8±0.6). 1) find total resistance if it is connected in parallel. 2) maximum %age error in resistance?
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R1= (6±0.2)Ω and R2 = (8±0.6). 1) find total resistance if it is connected in parallel. 2) maximum %age error in resistance? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about R1= (6±0.2)Ω and R2 = (8±0.6). 1) find total resistance if it is connected in parallel. 2) maximum %age error in resistance? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for R1= (6±0.2)Ω and R2 = (8±0.6). 1) find total resistance if it is connected in parallel. 2) maximum %age error in resistance?.
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