R1= (6±0.2)Ω and R2 = (8±0.6). 1) find total resistance if it is conne...
1) Calculation of total resistance:
When resistors are connected in parallel, the total resistance (Rt) can be calculated using the formula:
1/Rt = 1/R1 + 1/R2 + ...
In this case, R1 = (6±0.2)Ω and R2 = (8±0.6)Ω. To calculate the total resistance, we need to substitute the values of R1 and R2 into the formula.
1/Rt = 1/(6±0.2) + 1/(8±0.6)
To find the total resistance, we need to consider the maximum and minimum values of R1 and R2.
Using the maximum values:
1/Rt_max = 1/(6+0.2) + 1/(8+0.6)
= 1/6.2 + 1/8.6
Simplifying,
1/Rt_max = 0.161 + 0.116
= 0.277
Taking the reciprocal on both sides,
Rt_max = 1/0.277
≈ 3.61Ω
Using the minimum values:
1/Rt_min = 1/(6-0.2) + 1/(8-0.6)
= 1/5.8 + 1/7.4
Simplifying,
1/Rt_min = 0.172 + 0.135
= 0.307
Taking the reciprocal on both sides,
Rt_min = 1/0.307
≈ 3.26Ω
Therefore, the total resistance (Rt) when the resistors are connected in parallel is approximately 3.26Ω to 3.61Ω.
2) Calculation of maximum percentage error in resistance:
To calculate the maximum percentage error in resistance, we need to use the formula:
% error = (Max value - Min value) / Average value * 100
In this case, we have the maximum and minimum values of the total resistance, which are 3.61Ω and 3.26Ω, respectively. To calculate the average value, we can use the formula:
Average value = (Max value + Min value) / 2
Average value = (3.61 + 3.26) / 2
= 3.435Ω
Substituting the values into the formula:
% error = (3.61 - 3.26) / 3.435 * 100
= 0.35 / 3.435 * 100
≈ 10.19%
Therefore, the maximum percentage error in resistance is approximately 10.19%.
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