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On a long horizontally moving belt , a child runs to and fro with a speed 9 km h-1 (with respect to the belt) between his father and mother located 50 m apart on the moving belt. The belt moves with a speed of 4 . For an observer on a stationary platform outside, what is the (a) speed of the child running in the direction of motion of the belt ?. (b) speed of the child running opposite to the direction of motion of the belt ? (c) time taken by the child in (a) and (b) ?
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On a long horizontally moving belt , a child runs to and fro with a sp...
Speed of the child running in the direction of motion of the belt:
To determine the speed of the child running in the direction of motion of the belt, we need to consider the relative velocities of the child and the belt.

The child's speed with respect to the belt is given as 9 km/h. The belt's speed is given as 4 m/s.

Relative Velocity:
The relative velocity is the vector difference between the velocities of two objects. In this case, the relative velocity of the child with respect to the belt is given by:
Relative velocity = (Speed of the child with respect to the belt) - (Speed of the belt)
Relative velocity = 9 km/h - 4 km/h (converted to m/s)
Relative velocity = 5 km/h = 5 m/s

Speed of the child running in the direction of motion of the belt:
The child's speed in the direction of motion of the belt can be determined by adding the relative velocity to the speed of the belt.

Speed of the child running in the direction of motion of the belt = (Speed of the belt) + (Relative velocity)
Speed of the child running in the direction of motion of the belt = 4 m/s + 5 m/s
Speed of the child running in the direction of motion of the belt = 9 m/s

Time taken by the child in running in the direction of motion of the belt:
To determine the time taken by the child in running in the direction of motion of the belt, we need to consider the distance between the child's father and mother, which is given as 50 m.

Time = Distance / Speed
Time taken by the child in running in the direction of motion of the belt = 50 m / 9 m/s
Time taken by the child in running in the direction of motion of the belt = 5.56 seconds (approx.)

Speed of the child running opposite to the direction of motion of the belt:
The speed of the child running opposite to the direction of motion of the belt can be determined by subtracting the relative velocity from the speed of the belt.

Speed of the child running opposite to the direction of motion of the belt = (Speed of the belt) - (Relative velocity)
Speed of the child running opposite to the direction of motion of the belt = 4 m/s - 5 m/s
Speed of the child running opposite to the direction of motion of the belt = -1 m/s

Time taken by the child in running opposite to the direction of motion of the belt:
To determine the time taken by the child in running opposite to the direction of motion of the belt, we again consider the distance between the child's father and mother, which is given as 50 m.

Time = Distance / Speed
Time taken by the child in running opposite to the direction of motion of the belt = 50 m / (-1 m/s)
Time taken by the child in running opposite to the direction of motion of the belt = -50 seconds

The negative sign indicates that the child cannot run in the opposite direction of the belt's motion with a speed of 1 m/s. Therefore, it is not meaningful to consider the time taken in this case.
Community Answer
On a long horizontally moving belt , a child runs to and fro with a sp...
A)5kmph
b)13kmph
for a time


t=0.01hour
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On a long horizontally moving belt , a child runs to and fro with a speed 9 km h-1 (with respect to the belt) between his father and mother located 50 m apart on the moving belt. The belt moves with a speed of 4 . For an observer on a stationary platform outside, what is the (a) speed of the child running in the direction of motion of the belt ?. (b) speed of the child running opposite to the direction of motion of the belt ? (c) time taken by the child in (a) and (b) ?
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On a long horizontally moving belt , a child runs to and fro with a speed 9 km h-1 (with respect to the belt) between his father and mother located 50 m apart on the moving belt. The belt moves with a speed of 4 . For an observer on a stationary platform outside, what is the (a) speed of the child running in the direction of motion of the belt ?. (b) speed of the child running opposite to the direction of motion of the belt ? (c) time taken by the child in (a) and (b) ? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about On a long horizontally moving belt , a child runs to and fro with a speed 9 km h-1 (with respect to the belt) between his father and mother located 50 m apart on the moving belt. The belt moves with a speed of 4 . For an observer on a stationary platform outside, what is the (a) speed of the child running in the direction of motion of the belt ?. (b) speed of the child running opposite to the direction of motion of the belt ? (c) time taken by the child in (a) and (b) ? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for On a long horizontally moving belt , a child runs to and fro with a speed 9 km h-1 (with respect to the belt) between his father and mother located 50 m apart on the moving belt. The belt moves with a speed of 4 . For an observer on a stationary platform outside, what is the (a) speed of the child running in the direction of motion of the belt ?. (b) speed of the child running opposite to the direction of motion of the belt ? (c) time taken by the child in (a) and (b) ?.
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