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Find the coordinates of the point equidistant from the points A(1, 2), B (3, –4) and C(5, –6).

  • a)
    (2, 3)

  • b)
    (11, 2)

  • c)
    (0, 3)

  • d)
    (1, 3)

Correct answer is option 'B'. Can you explain this answer?
Most Upvoted Answer
Find the coordinates of the point equidistant from the points A(1, 2),...
The given three points are A(1,2) B(3,-4) and C(5,-6).

Let P (x, y) be the point equidistant from these three points.

So, PA = PB = PC


⇒ x^2 + 1– 2x + y^2 + 4 – 4y = x^2 + 9 -6x + y^2 + 16 + 8y = x 2 + 25– 10x + y^2 + 36 + 12y

⇒  – 2x– 4y + 5  = -6x + 8y +25=  – 10x + 12y+61
– 2x– 4y + 5  = -6x + 8y +25

⇒  – 2x– 4y + 5 +6x - 8y -25=0

⇒  4x– 12y -20=0

⇒  x– 3y - 5 =0....(i)

- 2x– 4y + 5  =  – 10x + 12y+61

⇒- 2x– 4y + 5 +10x - 12y-61=0

⇒8x– 16y -56=0

⇒x– 2y -7=0....(ii)

Solving (i) and (ii)

x = 11, y = 2

Thus, the required point is (11, 2)
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Find the coordinates of the point equidistant from the points A(1, 2),...
Finding the Co-ordinates of the Point Equidistant from Three Points

Given Points: A(1, 2), B(3, -4), and C(5, -6)

To find the point equidistant from three points, we need to follow the below steps:

Step 1: Find the Mid-point of AB and BC
- Mid-point of AB = [(1+3)/2, (2-4)/2] = (2,-1)
- Mid-point of BC = [(3+5)/2, (-4-6)/2] = (4,-5)

Step 2: Find the Slope of AB and BC
- Slope of AB = (2-(-4))/(1-3) = 3
- Slope of BC = (-6-(-4))/(5-3) = -1

Step 3: Find the Equation of Perpendicular Bisectors of AB and BC
- Equation of Perpendicular Bisector of AB passing through mid-point (2,-1) with slope m= -1/3 is y+1 = (-1/3)(x-2) i.e. 3y+x=5
- Equation of Perpendicular Bisector of BC passing through mid-point (4,-5) with slope m=1 is y+5 = (1)(x-4) i.e. y=x-9

Step 4: Find the Intersection Point of Both the Perpendicular Bisectors
- Solving the above two equations, we get the intersection point as (11,2)

Therefore, the point equidistant from A, B, and C is (11,2).

Hence, the correct answer is option B.
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