A person has acid costing Rs. 30 per liter. He mixed some water in it ...
Understanding the Problem
A person has acid costing Rs. 30 per liter and mixes it with water to sell the mixture at Rs. 40 per liter, achieving a 100% profit. We need to find the ratio of acid to water in the resultant mixture.
Calculating Selling Price and Cost Price
- Selling Price (SP) = Rs. 40 per liter
- Profit = 100%
- Therefore, Cost Price (CP) = SP / (1 + Profit Percentage)
- CP = 40 / (1 + 1) = Rs. 20 per liter
The cost of the mixture (which includes both acid and water) must equal Rs. 20 per liter.
Cost of Ingredients
- Let x be the quantity of acid in liters and y be the quantity of water in liters.
- The cost of acid = Rs. 30 * x
- The cost of water = Rs. 0 * y (since water is considered free for this problem)
The total cost of the mixture is:
Cost of mixture = Cost of acid + Cost of water = 30x + 0y = 30x
Finding the Mixture Cost
Since the mixture is sold at Rs. 20 per liter, we can express the total cost for the mixture (x + y) liters as:
30x / (x + y) = 20
Setting Up the Equation
Cross-multiplying gives us:
30x = 20(x + y)
Expanding and rearranging:
30x = 20x + 20y
10x = 20y
x/y = 20/10 = 2
Final Ratio of Acid to Water
Thus, the ratio of acid (x) to water (y) is:
Acid : Water = 2 : 1
The correct answer is option 'B'.
A person has acid costing Rs. 30 per liter. He mixed some water in it ...


Acid : Water= 20 : 10 = 2 : 1
Hence, Option B is correct.