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Factorize the quadratic polynomial by splitting the middle term: y2 – 4 y –21
- a)(y – 7) (y – 3)
- b)(y – 7) (y + 3)
- c)(y + 7) (y – 3)
- d)(y + 7) (y + 3)
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
Factorize the quadratic polynomial by splitting the middle term: y2&nd...
y2 – 4 y –21
y2 – 7 y + 3 y –21
y (y – 7) – 3 (y – 7)
(y – 7) (y – 3)
y2 – 7 y + 3 y –21
y (y – 7) – 3 (y – 7)
(y – 7) (y – 3)
Most Upvoted Answer
Factorize the quadratic polynomial by splitting the middle term: y2&nd...
+ 7y + 10
To factorize this quadratic polynomial, we need to find two numbers that multiply to give the constant term (10) and add to give the coefficient of the middle term (7).
The factors of 10 are:
1 x 10
2 x 5
Since we need the sum of the factors to be 7, we can see that 2 and 5 are the two numbers we are looking for.
So, we can rewrite the middle term as 2y + 5y:
y2 + 2y + 5y + 10
Now, we can group the first two terms and the last two terms together and factorize each group separately:
y(y + 2) + 5(y + 2)
Notice that both groups have a common factor of (y + 2), so we can factorize it out:
(y + 2)(y + 5)
Therefore, the factored form of the quadratic polynomial y2 + 7y + 10 is (y + 2)(y + 5).
To factorize this quadratic polynomial, we need to find two numbers that multiply to give the constant term (10) and add to give the coefficient of the middle term (7).
The factors of 10 are:
1 x 10
2 x 5
Since we need the sum of the factors to be 7, we can see that 2 and 5 are the two numbers we are looking for.
So, we can rewrite the middle term as 2y + 5y:
y2 + 2y + 5y + 10
Now, we can group the first two terms and the last two terms together and factorize each group separately:
y(y + 2) + 5(y + 2)
Notice that both groups have a common factor of (y + 2), so we can factorize it out:
(y + 2)(y + 5)
Therefore, the factored form of the quadratic polynomial y2 + 7y + 10 is (y + 2)(y + 5).
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Community Answer
Factorize the quadratic polynomial by splitting the middle term: y2&nd...
Here y^2-4y-21 splitting middle terms y^2 +3y-7y-21 (y^2+3y)-(7y-21) take common y(y+3)-7(y+3) (y+3)(y-7)
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Factorize the quadratic polynomial by splitting the middle term: y2– 4 y –21a)(y – 7) (y – 3)b)(y – 7) (y + 3)c)(y + 7) (y – 3)d)(y + 7) (y + 3)Correct answer is option 'B'. Can you explain this answer? for Class 9 2026 is part of Class 9 preparation. The Question and answers have been prepared according to the Class 9 exam syllabus. Information about Factorize the quadratic polynomial by splitting the middle term: y2– 4 y –21a)(y – 7) (y – 3)b)(y – 7) (y + 3)c)(y + 7) (y – 3)d)(y + 7) (y + 3)Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for Class 9 2026 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Factorize the quadratic polynomial by splitting the middle term: y2– 4 y –21a)(y – 7) (y – 3)b)(y – 7) (y + 3)c)(y + 7) (y – 3)d)(y + 7) (y + 3)Correct answer is option 'B'. Can you explain this answer?.
Factorize the quadratic polynomial by splitting the middle term: y2– 4 y –21a)(y – 7) (y – 3)b)(y – 7) (y + 3)c)(y + 7) (y – 3)d)(y + 7) (y + 3)Correct answer is option 'B'. Can you explain this answer? for Class 9 2026 is part of Class 9 preparation. The Question and answers have been prepared according to the Class 9 exam syllabus. Information about Factorize the quadratic polynomial by splitting the middle term: y2– 4 y –21a)(y – 7) (y – 3)b)(y – 7) (y + 3)c)(y + 7) (y – 3)d)(y + 7) (y + 3)Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for Class 9 2026 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Factorize the quadratic polynomial by splitting the middle term: y2– 4 y –21a)(y – 7) (y – 3)b)(y – 7) (y + 3)c)(y + 7) (y – 3)d)(y + 7) (y + 3)Correct answer is option 'B'. Can you explain this answer?.
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