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Factorize the quadratic polynomial by splitting the middle term: y2 – 4 y –21
- a)(y – 7) (y – 3)
- b)(y – 7) (y + 3)
- c)(y + 7) (y – 3)
- d)(y + 7) (y + 3)
Correct answer is option 'B'. Can you explain this answer?
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Most Upvoted Answer
Factorize the quadratic polynomial by splitting the middle term: y2&nd...
+ 7y + 10
To factorize this quadratic polynomial, we need to find two numbers that multiply to give the constant term (10) and add to give the coefficient of the middle term (7).
The factors of 10 are:
1 x 10
2 x 5
Since we need the sum of the factors to be 7, we can see that 2 and 5 are the two numbers we are looking for.
So, we can rewrite the middle term as 2y + 5y:
y2 + 2y + 5y + 10
Now, we can group the first two terms and the last two terms together and factorize each group separately:
y(y + 2) + 5(y + 2)
Notice that both groups have a common factor of (y + 2), so we can factorize it out:
(y + 2)(y + 5)
Therefore, the factored form of the quadratic polynomial y2 + 7y + 10 is (y + 2)(y + 5).
To factorize this quadratic polynomial, we need to find two numbers that multiply to give the constant term (10) and add to give the coefficient of the middle term (7).
The factors of 10 are:
1 x 10
2 x 5
Since we need the sum of the factors to be 7, we can see that 2 and 5 are the two numbers we are looking for.
So, we can rewrite the middle term as 2y + 5y:
y2 + 2y + 5y + 10
Now, we can group the first two terms and the last two terms together and factorize each group separately:
y(y + 2) + 5(y + 2)
Notice that both groups have a common factor of (y + 2), so we can factorize it out:
(y + 2)(y + 5)
Therefore, the factored form of the quadratic polynomial y2 + 7y + 10 is (y + 2)(y + 5).
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Factorize the quadratic polynomial by splitting the middle term: y2&nd...
Y^2 - 4y - 21=y^2-7y+3y-21 =y(y-7)+3(y-7) =(y-7) (y+3) I am in class 10.. So anyone can ask questions from me... I will explain them... Please subscribe me.. And bacome my friend
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Factorize the quadratic polynomial by splitting the middle term: y2– 4 y –21a)(y – 7) (y – 3)b)(y – 7) (y + 3)c)(y + 7) (y – 3)d)(y + 7) (y + 3)Correct answer is option 'B'. Can you explain this answer?
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