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In the reaction,               


2Al(s)+6HCl(aq) → 2Al 3+(aq)+6Cl-(aq)+3H2 (g),


[AIEEE 2007]

  • a)
    6L HCl(aq) is consumed for every 3L H2(g) produced

  • b)
    11.2 L H2(g) at STP is produced for every mole HCl(aq) consumed

  • c)
    67.2 L H2(g) at STP is produced for every mole Al that reacts

  • d)
    33.6 L H2(g) is produced regardless of temperature and pressure for every mole Al that reacts

Correct answer is option 'B'. Can you explain this answer?
Verified Answer
In the reaction,2Al(s)+6HCl(aq) → 2Al 3+(aq)+6Cl-(aq)+3H2 (g),[AI...
Correct Answer :- B
Explanation : 6 moles of HCl reacts with 3 moles of hydrogen.
Hence, 1 mole of HCl will react with 3/6 
= 0.5 moles of hydrogen.
At STP, 1 mole of hydrogen corresponds to 22.4 L.
Hence, 0.5 moles of hydrogen will correspond to 22.4/2 = 11.2L.
Thus, 11.2 L of hydrogen gas at STP is produced for every mole of HCl consumed.
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Most Upvoted Answer
In the reaction,2Al(s)+6HCl(aq) → 2Al 3+(aq)+6Cl-(aq)+3H2 (g),[AI...
2AlCl3(aq) 3H2(g)

Aluminum (Al) reacts with hydrochloric acid (HCl) to produce aluminum chloride (AlCl3) and hydrogen gas (H2).
Free Test
Community Answer
In the reaction,2Al(s)+6HCl(aq) → 2Al 3+(aq)+6Cl-(aq)+3H2 (g),[AI...
6mol HCl ~ 3mol H2
1mol HCl ~ 0.5mol H2
so, 1 mol H2 = 22.4L at STP
0.5 mol H2= ?x
X=0.5×22.4L÷1=11.2L H2 is produced for every one mole of HCL
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In the reaction,2Al(s)+6HCl(aq) → 2Al 3+(aq)+6Cl-(aq)+3H2 (g),[AIEEE 2007]a)6L HCl(aq) is consumed for every 3L H2(g) producedb)11.2 L H2(g) at STP is produced for every mole HCl(aq) consumedc)67.2 L H2(g) at STP is produced for every mole Al that reactsd)33.6 L H2(g) is produced regardless of temperature and pressure for every mole Al that reactsCorrect answer is option 'B'. Can you explain this answer?
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