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A 6-pole DC machine with lap winding has 300 conductors and a flux per pole of 15 mWb. If the machine is driven at 1800 rpm, then the average EMF induced per conductor will be:
- a)3.6 V
- b)2.7 V
- c)9 V
- d)162 V
Correct answer is option 'B'. Can you explain this answer?
Most Upvoted Answer
A 6-pole DC machine with lap winding has 300 conductors and a flux per...
Given, speed,
N= 1800 rpm
n = 1800/60 rps = 30 rps
Average emf induced per conductor
N= 1800 rpm
n = 1800/60 rps = 30 rps
Average emf induced per conductor
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A 6-pole DC machine with lap winding has 300 conductors and a flux per...
Understanding the Problem
To determine the average EMF induced per conductor in a 6-pole DC machine with lap winding, we can use the formula:
EMF = (P * Φ * N * n) / 60
Where:
- P = Number of poles
- Φ = Flux per pole (in Wb)
- N = Number of conductors
- n = Speed (in rpm)
Given Data
- Number of poles (P) = 6
- Flux per pole (Φ) = 15 mWb = 15 x 10^-3 Wb
- Number of conductors (N) = 300
- Speed (n) = 1800 rpm
Calculating the EMF
1. Convert Flux:
- Φ = 15 mWb = 0.015 Wb
2. Plug Values into the Formula:
- EMF = (6 * 0.015 * 300 * 1800) / 60
3. Calculate:
- EMF = (6 * 0.015 * 300 * 1800) / 60
- EMF = (6 * 0.015 * 300 * 30)
- EMF = (6 * 0.015 * 9000)
- EMF = (6 * 135)
- EMF = 810 V
However, since we are calculating the average EMF per conductor, we divide the total EMF by the number of conductors:
Average EMF per Conductor
- Average EMF per conductor = Total EMF / Number of conductors
- Average EMF per conductor = 810 V / 300
- Average EMF per conductor = 2.7 V
Conclusion
The average EMF induced per conductor is 2.7 V, making option 'B' the correct answer.
To determine the average EMF induced per conductor in a 6-pole DC machine with lap winding, we can use the formula:
EMF = (P * Φ * N * n) / 60
Where:
- P = Number of poles
- Φ = Flux per pole (in Wb)
- N = Number of conductors
- n = Speed (in rpm)
Given Data
- Number of poles (P) = 6
- Flux per pole (Φ) = 15 mWb = 15 x 10^-3 Wb
- Number of conductors (N) = 300
- Speed (n) = 1800 rpm
Calculating the EMF
1. Convert Flux:
- Φ = 15 mWb = 0.015 Wb
2. Plug Values into the Formula:
- EMF = (6 * 0.015 * 300 * 1800) / 60
3. Calculate:
- EMF = (6 * 0.015 * 300 * 1800) / 60
- EMF = (6 * 0.015 * 300 * 30)
- EMF = (6 * 0.015 * 9000)
- EMF = (6 * 135)
- EMF = 810 V
However, since we are calculating the average EMF per conductor, we divide the total EMF by the number of conductors:
Average EMF per Conductor
- Average EMF per conductor = Total EMF / Number of conductors
- Average EMF per conductor = 810 V / 300
- Average EMF per conductor = 2.7 V
Conclusion
The average EMF induced per conductor is 2.7 V, making option 'B' the correct answer.
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Question Description
A 6-pole DC machine with lap winding has 300 conductors and a flux per pole of 15 mWb. If the machine is driven at 1800 rpm, then the average EMF induced per conductor will be:a)3.6 Vb)2.7 Vc)9 Vd)162 VCorrect answer is option 'B'. Can you explain this answer? for Electrical Engineering (EE) 2026 is part of Electrical Engineering (EE) preparation. The Question and answers have been prepared according to the Electrical Engineering (EE) exam syllabus. Information about A 6-pole DC machine with lap winding has 300 conductors and a flux per pole of 15 mWb. If the machine is driven at 1800 rpm, then the average EMF induced per conductor will be:a)3.6 Vb)2.7 Vc)9 Vd)162 VCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for Electrical Engineering (EE) 2026 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A 6-pole DC machine with lap winding has 300 conductors and a flux per pole of 15 mWb. If the machine is driven at 1800 rpm, then the average EMF induced per conductor will be:a)3.6 Vb)2.7 Vc)9 Vd)162 VCorrect answer is option 'B'. Can you explain this answer?.
A 6-pole DC machine with lap winding has 300 conductors and a flux per pole of 15 mWb. If the machine is driven at 1800 rpm, then the average EMF induced per conductor will be:a)3.6 Vb)2.7 Vc)9 Vd)162 VCorrect answer is option 'B'. Can you explain this answer? for Electrical Engineering (EE) 2026 is part of Electrical Engineering (EE) preparation. The Question and answers have been prepared according to the Electrical Engineering (EE) exam syllabus. Information about A 6-pole DC machine with lap winding has 300 conductors and a flux per pole of 15 mWb. If the machine is driven at 1800 rpm, then the average EMF induced per conductor will be:a)3.6 Vb)2.7 Vc)9 Vd)162 VCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for Electrical Engineering (EE) 2026 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A 6-pole DC machine with lap winding has 300 conductors and a flux per pole of 15 mWb. If the machine is driven at 1800 rpm, then the average EMF induced per conductor will be:a)3.6 Vb)2.7 Vc)9 Vd)162 VCorrect answer is option 'B'. Can you explain this answer?.
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