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A train crosses an electric pole in 75 seconds. If the speed of the train is decreased by 25% and the length of the train is decreased by 80%, in how many seconds can it cross the same pole?
  • a)
    20
  • b)
    30
  • c)
    40
  • d)
    60
Correct answer is option 'A'. Can you explain this answer?
Most Upvoted Answer
A train crosses an electric pole in 75 seconds. If the speed of the tr...
Required time 

Hence, Option A is correct.
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Community Answer
A train crosses an electric pole in 75 seconds. If the speed of the tr...
Understanding the Problem
To solve the problem, we need to analyze the train's speed and length changes, and how they affect the time taken to cross an electric pole.
Initial Conditions
- Time taken to cross the pole = 75 seconds
- Let the original length of the train = L meters
- Speed of the train = S meters/second
Using the formula:
Time = Distance / Speed, we can express:
75 = L / S
=> L = 75S (Equation 1)
Changes in Speed and Length
- Speed is decreased by 25%:
- New speed = S - 0.25S = 0.75S
- Length is decreased by 80%:
- New length = L - 0.80L = 0.20L
Substituting Equation 1 into the new length:
New length = 0.20 * 75S = 15S
New Time Calculation
Now we calculate the new time required to cross the electric pole:
New Time = New Length / New Speed
= (15S) / (0.75S)
= 15 / 0.75
= 20 seconds
Final Answer
The time taken for the train to cross the same pole after the changes is 20 seconds. Thus, the correct answer is option 'A'.
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