An electron and proton enter a magnetic field with equal velocities. Which one of them experiences a greater force?a)electronb)protonc)Both experience same magnitude of forced)No prediction can be made.Correct answer is option 'C'. Can you explain this answer?

Question

Answer

It's right ans because both have same magnitude of charge.

Answer

Both of them have equal magnitude but opposite sign.

Answer

As F=qvB .... so having same magnitude of charge and same velocity ...they'll experience same magnitude of force

Answer

Yes the answer is c as both electron and proton have same magnitude of the charge but they are opposite in value.......

Answer

As charges and velocities are same
F=q(V×B)
So having the same magnitude of charge and same velocity, they'll experience the same magnitude of force.

Answer

F =qbvsinQ age charge ki value same h to force nhi same hoga bs dirn alg hogi dono ki

Answer

Explanation:

When a charged particle enters a magnetic field, it experiences a force called the magnetic force. The magnitude and direction of this force depend on the charge and velocity of the particle, as well as the strength and direction of the magnetic field.

Magnetic Force on a Charged Particle:
The magnetic force on a charged particle moving in a magnetic field is given by the equation:

F = q * (v x B)

Where:
- F is the magnetic force on the particle
- q is the charge of the particle
- v is the velocity of the particle
- B is the magnetic field

Comparison of Electron and Proton:
1. Charge:
- An electron has a charge of -1.6 x 10^(-19) C (negative charge)
- A proton has a charge of +1.6 x 10^(-19) C (positive charge)

2. Velocity:
- The question states that the electron and proton have equal velocities. Let's assume this velocity is v.

3. Magnetic Force:
- The magnitude of the magnetic force is given by F = q * (v x B).

Calculating the Magnetic Force:
Substituting the values for charge and velocity for both the electron and the proton, we get:

For the electron:
F_e = (-1.6 x 10^(-19) C) * (v x B) = -1.6 x 10^(-19) * (v x B)

For the proton:
F_p = (1.6 x 10^(-19) C) * (v x B) = 1.6 x 10^(-19) * (v x B)

Comparison of Forces:
Comparing the magnitudes of the forces:

|F_e| = |-1.6 x 10^(-19) * (v x B)| = 1.6 x 10^(-19) * |v x B|
|F_p| = |1.6 x 10^(-19) * (v x B)| = 1.6 x 10^(-19) * |v x B|

As we can see, the magnitudes of the forces are equal for both the electron and the proton, regardless of the direction of the magnetic field or the velocity of the particles.

Conclusion:
Therefore, both the electron and proton experience the same magnitude of force when entering a magnetic field with equal velocities.

Answer

As charges and velocities are same
F=q(V×B)
So having the same magnitude of charge and same velocity, they'll experience the same magnitude of force.

Answer

As charges and velocities are same
F=q(V×B)
So having the same magnitude of charge and same velocity, they'll experience the same magnitude of force.

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