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Direction (Q. Nos. 18 and 19) This section contains 2 questions. when worked out will result in an integer from 0 to 9 (both inclusive)
Q.  has two types of sulphur atoms. What is the difference in the oxidation states of two types of sulphur atoms?
    Correct answer is '8'. Can you explain this answer?
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    Direction (Q. Nos. 18 and 19) This section contains 2questions. when w...
    In ion S2O3(2-) , There are two sulphur atoms are present in the structure , as one sulphur atom is opposite to another. Sulphur atom has Oxidation state of +6, and another one is in the oxidation state of -2 as same as O atom in the structure.

    The most common oxidation states of  S are (-2,+4 and +6)  the Ion S2O3(2-) which is S-SO3 is a combination of S(2-) and S(6+). 
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    Direction (Q. Nos. 18 and 19) This section contains 2questions. when w...
    Explanation:
    To understand the difference in the oxidation states of the two types of sulphur atoms in S2O32-, we need to first determine the oxidation states of each sulphur atom.

    Step 1: Identify the oxidation state of one sulphur atom
    Let's assume that one of the sulphur atoms has an oxidation state of x.

    Step 2: Determine the oxidation state of the other sulphur atom
    Since the overall charge of the ion is -2, and there are three oxygen atoms with a charge of -2 each, the total negative charge contributed by the oxygen atoms is -6.

    Therefore, the sum of the oxidation states of the two sulphur atoms must be +6 to balance the negative charge.

    Step 3: Calculate the oxidation state of the other sulphur atom
    Let's assume that the oxidation state of the other sulphur atom is y.

    The sum of the oxidation states of the two sulphur atoms is x + y. Since the sum must be +6, we have the equation:

    x + y = +6

    Step 4: Determine the difference in the oxidation states
    To find the difference in the oxidation states, we subtract the two oxidation states:

    Difference = y - x

    Step 5: Solve the equations
    We have two equations:

    x + y = +6
    Difference = y - x

    Solving these equations, we find that x = -2 and y = +4.

    Step 6: Calculate the difference in the oxidation states
    Substituting the values of x and y into the equation for the difference, we have:

    Difference = (4) - (-2) = 4 + 2 = 6

    Therefore, the difference in the oxidation states of the two types of sulphur atoms in S2O32- is 6.

    Conclusion:
    The correct answer is 6, not 8.
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    Direction (Q. Nos. 18 and 19) This section contains 2questions. when worked out will result in an integer from 0 to 9 (both inclusive)Q. has two types of sulphur atoms. What is the difference in the oxidation states of two types of sulphur atoms?Correct answer is '8'. Can you explain this answer?
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