Class 9 Exam  >  Class 9 Questions  >  A stone is dropped down a deep from rest. The... Start Learning for Free
A stone is dropped down a deep from rest. The well is 50m.deep. how long will it take to reach the bottom of well? (acc.=9.8m/s?
Verified Answer
A stone is dropped down a deep from rest. The well is 50m.deep. how lo...
Given  that,

a  =  9.8 m/s2

u  =  0

s  =  50m



By  Newton's  law  of  motion,

v2  -  u2  =  2as,

ie,  v2  -  [0]2  =  2 * 9.8 * 50

ie,  v2  =  980.

So,  v  =  Root  of  980

=  31.304....



Now,  we  got  the  final  velocity  v.

So,  we  can  find  the  time  required,  by  Newton's  equation  of motion,

v  =  u  +  at.

ie,  31.304  =  0  +  9.8 * t

31.304  =  9.8t

So,  t  =  31.304  /  9.8

ie,  31.30 * 100  /  9.8 * 100

=  3130  /  980

=  3.193....m / s.
This question is part of UPSC exam. View all Class 9 courses
Most Upvoted Answer
A stone is dropped down a deep from rest. The well is 50m.deep. how lo...
Given,
u=0 m/s
S=50 m
g=9.8 m/(s^2)   (for freely falling body,g is +ve)
t=?
For a freely falling body dropped from rest,
S=1/2g*t^2    (S=ut+1/2a*t^2=>S=0+1/2g*t^2=>S=1/2g*t^2)
50=1/2*9.8*t^2
t^2=50*2/9.8
t^2=10.204
=>t=(10.204)^1/2
=>t=3.19 sec
hence,it will take 3.19 sec to reach bottom of the well.
Community Answer
A stone is dropped down a deep from rest. The well is 50m.deep. how lo...
Given, u = 0 m/s. u = Initial velocity v = ? v = Final velocity D = 50m. D = Distance A = 9.8m/s. A = Acceleration T = ? T = Time We know, v²-u² = 2as So, v²-0² = 2 × 9.8 × 50 v² = 980 v = 31.304...m/s TIME. S = ut + 1/2 at² 50 = 0t + 1/2 × 9.8 × t² 50 = 0 + 4.9t² 50 = 4.9t² 50/4.9 = t² 10.2 = t² 3.1937 sec = tHOPE IT HELPED 🙂
Attention Class 9 Students!
To make sure you are not studying endlessly, EduRev has designed Class 9 study material, with Structured Courses, Videos, & Test Series. Plus get personalized analysis, doubt solving and improvement plans to achieve a great score in Class 9.
Explore Courses for Class 9 exam

Top Courses for Class 9

A stone is dropped down a deep from rest. The well is 50m.deep. how long will it take to reach the bottom of well? (acc.=9.8m/s?
Question Description
A stone is dropped down a deep from rest. The well is 50m.deep. how long will it take to reach the bottom of well? (acc.=9.8m/s? for Class 9 2024 is part of Class 9 preparation. The Question and answers have been prepared according to the Class 9 exam syllabus. Information about A stone is dropped down a deep from rest. The well is 50m.deep. how long will it take to reach the bottom of well? (acc.=9.8m/s? covers all topics & solutions for Class 9 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A stone is dropped down a deep from rest. The well is 50m.deep. how long will it take to reach the bottom of well? (acc.=9.8m/s?.
Solutions for A stone is dropped down a deep from rest. The well is 50m.deep. how long will it take to reach the bottom of well? (acc.=9.8m/s? in English & in Hindi are available as part of our courses for Class 9. Download more important topics, notes, lectures and mock test series for Class 9 Exam by signing up for free.
Here you can find the meaning of A stone is dropped down a deep from rest. The well is 50m.deep. how long will it take to reach the bottom of well? (acc.=9.8m/s? defined & explained in the simplest way possible. Besides giving the explanation of A stone is dropped down a deep from rest. The well is 50m.deep. how long will it take to reach the bottom of well? (acc.=9.8m/s?, a detailed solution for A stone is dropped down a deep from rest. The well is 50m.deep. how long will it take to reach the bottom of well? (acc.=9.8m/s? has been provided alongside types of A stone is dropped down a deep from rest. The well is 50m.deep. how long will it take to reach the bottom of well? (acc.=9.8m/s? theory, EduRev gives you an ample number of questions to practice A stone is dropped down a deep from rest. The well is 50m.deep. how long will it take to reach the bottom of well? (acc.=9.8m/s? tests, examples and also practice Class 9 tests.
Explore Courses for Class 9 exam

Top Courses for Class 9

Explore Courses
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
10M+ students study on EduRev