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In the activity where you take two teaspoonfuls of distilled water in a clean, dry plastic or rubber cap, test its conductivity, and then dissolve a pinch of common salt in it before testing again, what is the result after adding the salt?
- a)The solution remains a poor conductor.
- b)The solution becomes a good conductor.
- c)The tester bulb explodes.
- d)No change in conductivity is observed.
Correct answer is option 'B'. Can you explain this answer?
Most Upvoted Answer
In the activity where you take two teaspoonfuls of distilled water in ...
The activity demonstrates that pure distilled water is a poor conductor, but after dissolving common salt, the resulting salt solution conducts electricity, making it a good conductor due to the presence of ions.
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In the activity where you take two teaspoonfuls of distilled water in ...
Conductivity of Distilled Water
When you initially test the conductivity of distilled water, you'll find it to be a poor conductor of electricity. This is because distilled water is free from impurities and dissolved ions that facilitate the flow of electric current.
Role of Salt in Conductivity
When you add a pinch of common salt (sodium chloride) to the distilled water, the following occurs:
- Dissociation of Salt: Sodium chloride (NaCl) dissociates into sodium ions (Na+) and chloride ions (Cl-) when it dissolves in water.
- Ion Formation: These ions are charged particles that can move freely in the solution.
Improved Conductivity
- Enhanced Conductivity: The presence of these free ions significantly improves the solution's ability to conduct electricity.
- Good Conductor: As a result, after adding salt, the solution becomes a good conductor of electricity, allowing the tester bulb to light up brightly.
Conclusion
Thus, the correct answer is option 'B': The solution becomes a good conductor. This experiment highlights how the presence of ions, like those from common salt, can transform a non-conductive solution into one that effectively conducts electricity.
When you initially test the conductivity of distilled water, you'll find it to be a poor conductor of electricity. This is because distilled water is free from impurities and dissolved ions that facilitate the flow of electric current.
Role of Salt in Conductivity
When you add a pinch of common salt (sodium chloride) to the distilled water, the following occurs:
- Dissociation of Salt: Sodium chloride (NaCl) dissociates into sodium ions (Na+) and chloride ions (Cl-) when it dissolves in water.
- Ion Formation: These ions are charged particles that can move freely in the solution.
Improved Conductivity
- Enhanced Conductivity: The presence of these free ions significantly improves the solution's ability to conduct electricity.
- Good Conductor: As a result, after adding salt, the solution becomes a good conductor of electricity, allowing the tester bulb to light up brightly.
Conclusion
Thus, the correct answer is option 'B': The solution becomes a good conductor. This experiment highlights how the presence of ions, like those from common salt, can transform a non-conductive solution into one that effectively conducts electricity.
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In the activity where you take two teaspoonfuls of distilled water in a clean, dry plastic or rubber cap, test its conductivity, and then dissolve a pinch of common salt in it before testing again, what is the result after adding the salt?a)The solution remains a poor conductor.b)The solution becomes a good conductor.c)The tester bulb explodes.d)No change in conductivity is observed.Correct answer is option 'B'. Can you explain this answer? for Class 8 2026 is part of Class 8 preparation. The Question and answers have been prepared according to the Class 8 exam syllabus. Information about In the activity where you take two teaspoonfuls of distilled water in a clean, dry plastic or rubber cap, test its conductivity, and then dissolve a pinch of common salt in it before testing again, what is the result after adding the salt?a)The solution remains a poor conductor.b)The solution becomes a good conductor.c)The tester bulb explodes.d)No change in conductivity is observed.Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for Class 8 2026 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for In the activity where you take two teaspoonfuls of distilled water in a clean, dry plastic or rubber cap, test its conductivity, and then dissolve a pinch of common salt in it before testing again, what is the result after adding the salt?a)The solution remains a poor conductor.b)The solution becomes a good conductor.c)The tester bulb explodes.d)No change in conductivity is observed.Correct answer is option 'B'. Can you explain this answer?.
In the activity where you take two teaspoonfuls of distilled water in a clean, dry plastic or rubber cap, test its conductivity, and then dissolve a pinch of common salt in it before testing again, what is the result after adding the salt?a)The solution remains a poor conductor.b)The solution becomes a good conductor.c)The tester bulb explodes.d)No change in conductivity is observed.Correct answer is option 'B'. Can you explain this answer? for Class 8 2026 is part of Class 8 preparation. The Question and answers have been prepared according to the Class 8 exam syllabus. Information about In the activity where you take two teaspoonfuls of distilled water in a clean, dry plastic or rubber cap, test its conductivity, and then dissolve a pinch of common salt in it before testing again, what is the result after adding the salt?a)The solution remains a poor conductor.b)The solution becomes a good conductor.c)The tester bulb explodes.d)No change in conductivity is observed.Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for Class 8 2026 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for In the activity where you take two teaspoonfuls of distilled water in a clean, dry plastic or rubber cap, test its conductivity, and then dissolve a pinch of common salt in it before testing again, what is the result after adding the salt?a)The solution remains a poor conductor.b)The solution becomes a good conductor.c)The tester bulb explodes.d)No change in conductivity is observed.Correct answer is option 'B'. Can you explain this answer?.
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