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A sample of water from a large swimming pool has a resistance of 10000 ohm at 25ºC when placed in a certain conductance cell. When filled with 0.02 M KCl solution, the cell has a resistance of 100 ohm at 25ºC. 585 gm of NaCl were dissolved in the pool, which was throughly stirred. A sample of this solution gave a resistance of 8000 Ω.
[Given : Molar conductance of NaCl at that concentration is 125 ohm-1cm2mol-1 and molar conductivity of KCl at 0.02 M is 200 Ω-1cm2 mol-1.]
Q.
Conductivity (Scm-1) of H2O is :
- a)4 × 10-2
- b)4 × 10-3
- c)4 × 10-5
- d)None of these
Correct answer is option 'C'. Can you explain this answer?
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A sample of water from a large swimming pool has a resistance of 10000...
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A sample of water from a large swimming pool has a resistance of 10000...
Given information:
- Resistance of water sample from swimming pool (pure water): 10000 ohm
- Resistance of 0.02 M KCl solution: 100 ohm
- Resistance of NaCl solution: 8000 ohm
- Molar conductance of NaCl at 0.02 M: 125 ohm-1cm2mol-1
- Molar conductance of KCl at 0.02 M: 200 ohm-1cm2mol-1
We need to find the conductivity of water (H2O). Conductivity is the reciprocal of resistance, so we can calculate the conductivity using the formula:
Conductivity (S/cm) = 1 / Resistance (ohm)
Let's calculate the conductivities for each scenario and compare them:
1. Conductivity of pure water:
Resistance = 10000 ohm
Conductivity (S/cm) = 1 / 10000 = 0.0001 S/cm
2. Conductivity of 0.02 M KCl solution:
Resistance = 100 ohm
Conductivity (S/cm) = 1 / 100 = 0.01 S/cm
3. Conductivity of NaCl solution:
Resistance = 8000 ohm
Conductivity (S/cm) = 1 / 8000 = 0.000125 S/cm
From the given molar conductances, we can calculate the conductivity of NaCl and KCl solutions using the formula:
Conductivity (S/cm) = Molar Conductance (ohm-1cm2mol-1) * Concentration (M)
4. Conductivity of 0.02 M KCl solution using molar conductance:
Conductivity (S/cm) = 200 ohm-1cm2mol-1 * 0.02 M = 4 S/cm
5. Conductivity of NaCl solution using molar conductance:
Conductivity (S/cm) = 125 ohm-1cm2mol-1 * Concentration (M)
We need to find the concentration of NaCl solution. The molar mass of NaCl is 58.5 g/mol. We have 585 g of NaCl dissolved in the pool, so the concentration can be calculated as:
Concentration (M) = Mass (g) / Molar Mass (g/mol) = 585 g / 58.5 g/mol = 10 M
Now we can calculate the conductivity of NaCl solution:
Conductivity (S/cm) = 125 ohm-1cm2mol-1 * 10 M = 1250 S/cm
Comparing the conductivities:
- Conductivity of pure water: 0.0001 S/cm
- Conductivity of 0.02 M KCl solution: 0.01 S/cm
- Conductivity of NaCl solution: 0.000125 S/cm
- Conductivity of 0.02 M KCl solution using molar conductance: 4 S/cm
- Conductivity of NaCl solution using molar conductance: 1250 S/cm
From the comparison, we can see that the conductivity of pure water is the lowest among all the solutions. Therefore, the conductivity of H2O is 4 x 10^-5 S/cm, which corresponds to option C.
- Resistance of water sample from swimming pool (pure water): 10000 ohm
- Resistance of 0.02 M KCl solution: 100 ohm
- Resistance of NaCl solution: 8000 ohm
- Molar conductance of NaCl at 0.02 M: 125 ohm-1cm2mol-1
- Molar conductance of KCl at 0.02 M: 200 ohm-1cm2mol-1
We need to find the conductivity of water (H2O). Conductivity is the reciprocal of resistance, so we can calculate the conductivity using the formula:
Conductivity (S/cm) = 1 / Resistance (ohm)
Let's calculate the conductivities for each scenario and compare them:
1. Conductivity of pure water:
Resistance = 10000 ohm
Conductivity (S/cm) = 1 / 10000 = 0.0001 S/cm
2. Conductivity of 0.02 M KCl solution:
Resistance = 100 ohm
Conductivity (S/cm) = 1 / 100 = 0.01 S/cm
3. Conductivity of NaCl solution:
Resistance = 8000 ohm
Conductivity (S/cm) = 1 / 8000 = 0.000125 S/cm
From the given molar conductances, we can calculate the conductivity of NaCl and KCl solutions using the formula:
Conductivity (S/cm) = Molar Conductance (ohm-1cm2mol-1) * Concentration (M)
4. Conductivity of 0.02 M KCl solution using molar conductance:
Conductivity (S/cm) = 200 ohm-1cm2mol-1 * 0.02 M = 4 S/cm
5. Conductivity of NaCl solution using molar conductance:
Conductivity (S/cm) = 125 ohm-1cm2mol-1 * Concentration (M)
We need to find the concentration of NaCl solution. The molar mass of NaCl is 58.5 g/mol. We have 585 g of NaCl dissolved in the pool, so the concentration can be calculated as:
Concentration (M) = Mass (g) / Molar Mass (g/mol) = 585 g / 58.5 g/mol = 10 M
Now we can calculate the conductivity of NaCl solution:
Conductivity (S/cm) = 125 ohm-1cm2mol-1 * 10 M = 1250 S/cm
Comparing the conductivities:
- Conductivity of pure water: 0.0001 S/cm
- Conductivity of 0.02 M KCl solution: 0.01 S/cm
- Conductivity of NaCl solution: 0.000125 S/cm
- Conductivity of 0.02 M KCl solution using molar conductance: 4 S/cm
- Conductivity of NaCl solution using molar conductance: 1250 S/cm
From the comparison, we can see that the conductivity of pure water is the lowest among all the solutions. Therefore, the conductivity of H2O is 4 x 10^-5 S/cm, which corresponds to option C.
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A sample of water from a large swimming pool has a resistance of 10000 ohm at 25ºC when placed in a certain conductance cell. When filled with 0.02 M KCl solution, the cell has a resistance of 100 ohm at 25ºC. 585 gm of NaCl were dissolved in the pool, which was throughly stirred. A sample of this solution gave a resistance of 8000 Ω.[Given : Molar conductance of NaCl at that concentration is 125 ohm-1cm2mol-1and molar conductivity of KCl at 0.02 M is 200 Ω-1cm2mol-1.]Q. Conductivity (Scm-1) of H2O is :a)4 × 10-2b)4 × 10-3c)4 × 10-5d)None of theseCorrect answer is option 'C'. Can you explain this answer?
Question Description
A sample of water from a large swimming pool has a resistance of 10000 ohm at 25ºC when placed in a certain conductance cell. When filled with 0.02 M KCl solution, the cell has a resistance of 100 ohm at 25ºC. 585 gm of NaCl were dissolved in the pool, which was throughly stirred. A sample of this solution gave a resistance of 8000 Ω.[Given : Molar conductance of NaCl at that concentration is 125 ohm-1cm2mol-1and molar conductivity of KCl at 0.02 M is 200 Ω-1cm2mol-1.]Q. Conductivity (Scm-1) of H2O is :a)4 × 10-2b)4 × 10-3c)4 × 10-5d)None of theseCorrect answer is option 'C'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about A sample of water from a large swimming pool has a resistance of 10000 ohm at 25ºC when placed in a certain conductance cell. When filled with 0.02 M KCl solution, the cell has a resistance of 100 ohm at 25ºC. 585 gm of NaCl were dissolved in the pool, which was throughly stirred. A sample of this solution gave a resistance of 8000 Ω.[Given : Molar conductance of NaCl at that concentration is 125 ohm-1cm2mol-1and molar conductivity of KCl at 0.02 M is 200 Ω-1cm2mol-1.]Q. Conductivity (Scm-1) of H2O is :a)4 × 10-2b)4 × 10-3c)4 × 10-5d)None of theseCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A sample of water from a large swimming pool has a resistance of 10000 ohm at 25ºC when placed in a certain conductance cell. When filled with 0.02 M KCl solution, the cell has a resistance of 100 ohm at 25ºC. 585 gm of NaCl were dissolved in the pool, which was throughly stirred. A sample of this solution gave a resistance of 8000 Ω.[Given : Molar conductance of NaCl at that concentration is 125 ohm-1cm2mol-1and molar conductivity of KCl at 0.02 M is 200 Ω-1cm2mol-1.]Q. Conductivity (Scm-1) of H2O is :a)4 × 10-2b)4 × 10-3c)4 × 10-5d)None of theseCorrect answer is option 'C'. Can you explain this answer?.
A sample of water from a large swimming pool has a resistance of 10000 ohm at 25ºC when placed in a certain conductance cell. When filled with 0.02 M KCl solution, the cell has a resistance of 100 ohm at 25ºC. 585 gm of NaCl were dissolved in the pool, which was throughly stirred. A sample of this solution gave a resistance of 8000 Ω.[Given : Molar conductance of NaCl at that concentration is 125 ohm-1cm2mol-1and molar conductivity of KCl at 0.02 M is 200 Ω-1cm2mol-1.]Q. Conductivity (Scm-1) of H2O is :a)4 × 10-2b)4 × 10-3c)4 × 10-5d)None of theseCorrect answer is option 'C'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about A sample of water from a large swimming pool has a resistance of 10000 ohm at 25ºC when placed in a certain conductance cell. When filled with 0.02 M KCl solution, the cell has a resistance of 100 ohm at 25ºC. 585 gm of NaCl were dissolved in the pool, which was throughly stirred. A sample of this solution gave a resistance of 8000 Ω.[Given : Molar conductance of NaCl at that concentration is 125 ohm-1cm2mol-1and molar conductivity of KCl at 0.02 M is 200 Ω-1cm2mol-1.]Q. Conductivity (Scm-1) of H2O is :a)4 × 10-2b)4 × 10-3c)4 × 10-5d)None of theseCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A sample of water from a large swimming pool has a resistance of 10000 ohm at 25ºC when placed in a certain conductance cell. When filled with 0.02 M KCl solution, the cell has a resistance of 100 ohm at 25ºC. 585 gm of NaCl were dissolved in the pool, which was throughly stirred. A sample of this solution gave a resistance of 8000 Ω.[Given : Molar conductance of NaCl at that concentration is 125 ohm-1cm2mol-1and molar conductivity of KCl at 0.02 M is 200 Ω-1cm2mol-1.]Q. Conductivity (Scm-1) of H2O is :a)4 × 10-2b)4 × 10-3c)4 × 10-5d)None of theseCorrect answer is option 'C'. Can you explain this answer?.
Solutions for A sample of water from a large swimming pool has a resistance of 10000 ohm at 25ºC when placed in a certain conductance cell. When filled with 0.02 M KCl solution, the cell has a resistance of 100 ohm at 25ºC. 585 gm of NaCl were dissolved in the pool, which was throughly stirred. A sample of this solution gave a resistance of 8000 Ω.[Given : Molar conductance of NaCl at that concentration is 125 ohm-1cm2mol-1and molar conductivity of KCl at 0.02 M is 200 Ω-1cm2mol-1.]Q. Conductivity (Scm-1) of H2O is :a)4 × 10-2b)4 × 10-3c)4 × 10-5d)None of theseCorrect answer is option 'C'. Can you explain this answer? in English & in Hindi are available as part of our courses for JEE.
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A sample of water from a large swimming pool has a resistance of 10000 ohm at 25ºC when placed in a certain conductance cell. When filled with 0.02 M KCl solution, the cell has a resistance of 100 ohm at 25ºC. 585 gm of NaCl were dissolved in the pool, which was throughly stirred. A sample of this solution gave a resistance of 8000 Ω.[Given : Molar conductance of NaCl at that concentration is 125 ohm-1cm2mol-1and molar conductivity of KCl at 0.02 M is 200 Ω-1cm2mol-1.]Q. Conductivity (Scm-1) of H2O is :a)4 × 10-2b)4 × 10-3c)4 × 10-5d)None of theseCorrect answer is option 'C'. Can you explain this answer?, a detailed solution for A sample of water from a large swimming pool has a resistance of 10000 ohm at 25ºC when placed in a certain conductance cell. When filled with 0.02 M KCl solution, the cell has a resistance of 100 ohm at 25ºC. 585 gm of NaCl were dissolved in the pool, which was throughly stirred. A sample of this solution gave a resistance of 8000 Ω.[Given : Molar conductance of NaCl at that concentration is 125 ohm-1cm2mol-1and molar conductivity of KCl at 0.02 M is 200 Ω-1cm2mol-1.]Q. Conductivity (Scm-1) of H2O is :a)4 × 10-2b)4 × 10-3c)4 × 10-5d)None of theseCorrect answer is option 'C'. Can you explain this answer? has been provided alongside types of A sample of water from a large swimming pool has a resistance of 10000 ohm at 25ºC when placed in a certain conductance cell. When filled with 0.02 M KCl solution, the cell has a resistance of 100 ohm at 25ºC. 585 gm of NaCl were dissolved in the pool, which was throughly stirred. A sample of this solution gave a resistance of 8000 Ω.[Given : Molar conductance of NaCl at that concentration is 125 ohm-1cm2mol-1and molar conductivity of KCl at 0.02 M is 200 Ω-1cm2mol-1.]Q. Conductivity (Scm-1) of H2O is :a)4 × 10-2b)4 × 10-3c)4 × 10-5d)None of theseCorrect answer is option 'C'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice A sample of water from a large swimming pool has a resistance of 10000 ohm at 25ºC when placed in a certain conductance cell. When filled with 0.02 M KCl solution, the cell has a resistance of 100 ohm at 25ºC. 585 gm of NaCl were dissolved in the pool, which was throughly stirred. A sample of this solution gave a resistance of 8000 Ω.[Given : Molar conductance of NaCl at that concentration is 125 ohm-1cm2mol-1and molar conductivity of KCl at 0.02 M is 200 Ω-1cm2mol-1.]Q. Conductivity (Scm-1) of H2O is :a)4 × 10-2b)4 × 10-3c)4 × 10-5d)None of theseCorrect answer is option 'C'. Can you explain this answer? tests, examples and also practice JEE tests.
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