In an adiabatic process gas is reduced to qua...

### Related Test In an adiabatic process gas is reduced to quarter of its volume. What would happen to its pressure? Given ratio of specific heats γ= 2
a)10 times increas
e
b)10 times decrease
c)16 times decrease
d)16 times increase Ciel Knowledge Explanation : The adiabatic condition is given by the relation between pressure volume and temperature volume as:
(PV)γ = constant
where, γ = Cp/Cv is ratio of the specific heats
These relations suggest that an decrease in volume is associated with increase in temperature

ATQ
P1(V1)γ = (P2V2
=> P1(1)2 = P2(4)2
P1/P2 = 16

 1 Crore+ students have signed up on EduRev. Have you? Deepika Jain
In an adiabatic process gas is reduced to quarter of its volume. What would happen to its pressure? Given ratio of specific heats γ= 2a)10 times increaseb)10 times decreasec)16 times decreased)16 times increaseCorrect answer is option 'C'. Can you explain this answer? View courses related to this question Explore Class 11 courses
 Explore Class 11 coursesView courses related to this question  Vikas Saini
Dhenya Mehta,when you don^t know answer,please don^t be a Einstein,correct answer is D,everyone should report this question Mammu Saleem
In an adiabatic process gas is reduced to quarter of its volume. What would happen to its pressure? Given ratio of specific heats γ= 2a)10 times increaseb)10 times decreasec)16 times decreased)16 times increaseCorrect answer is option 'C'. Can you explain this answer?
Ya the crt answer is d Sadaf Shaikh
Answer should be d. Because we hav
P1/p2=1/16 so the answer will be d Dhanya Mehta
In an adiabatic process gas is reduced to quarter of its volume. What would happen to its pressure? Given ratio of specific heats γ= 2a)10 times increaseb)10 times decreasec)16 times decreased)16 times increaseCorrect answer is option 'C'. Can you explain this answer?
P1/p2=1/16 so,
p1=p2/16 so correct answer is Ddecrease by 16

Question Description
Solutions for In an adiabatic process gas is reduced to quarter of its volume. What would happen to its pressure? Given ratio of specific heats γ= 2a)10 times increaseb)10 times decreasec)16 times decreased)16 times increaseCorrect answer is option 'C'. Can you explain this answer? in English & in Hindi are available as part of our courses for Class 11. Download more important topics, notes, lectures and mock test series for Class 11 Exam by signing up for free.

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