Class 11 Question > In an adiabatic process gas is reduced to qua...
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In an adiabatic process gas is reduced to quarter of its volume. What would happen to its pressure? Given ratio of specific heats γ= 2
a)10 times increas
eb)10 times decrease
c)16 times decrease
d)16 times increase
Correct answer is option 'C'. Can you explain this answer?
Answers
Correct Answer : C
Explanation : The adiabatic condition is given by the relation between pressure volume and temperature volume as:
(PV)γ = constant
where, γ = Cp/Cv is ratio of the specific heats
These relations suggest that an decrease in volume is associated with increase in temperature
ATQ
P1(V1)γ = (P2V2)γ
=> P1(1)2 = P2(4)2
P1/P2 = 16
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In an adiabatic process gas is reduced to quarter of its volume. What would happen to its pressure? Given ratio of specific heats γ= 2a)10 times increaseb)10 times decreasec)16 times decreased)16 times increaseCorrect answer is option 'C'. Can you explain this answer?
The answer should be d
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Dhenya Mehta,when you don^t know answer,please don^t be a Einstein,correct answer is D,everyone should report this question
In an adiabatic process gas is reduced to quarter of its volume. What would happen to its pressure? Given ratio of specific heats γ= 2a)10 times increaseb)10 times decreasec)16 times decreased)16 times increaseCorrect answer is option 'C'. Can you explain this answer?
Ya the crt answer is d
In an adiabatic process gas is reduced to quarter of its volume. What would happen to its pressure? Given ratio of specific heats γ= 2a)10 times increaseb)10 times decreasec)16 times decreased)16 times increaseCorrect answer is option 'C'. Can you explain this answer?
P1/p2=1/16 so,
p1=p2/16 so correct answer is Ddecrease by 16
p1=p2/16 so correct answer is Ddecrease by 16
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In an adiabatic process gas is reduced to quarter of its volume. What would happen to its pressure? Given ratio of specific heats γ= 2a)10 times increaseb)10 times decreasec)16 times decreased)16 times increaseCorrect answer is option 'C'. Can you explain this answer? for Class 11 2023 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about In an adiabatic process gas is reduced to quarter of its volume. What would happen to its pressure? Given ratio of specific heats γ= 2a)10 times increaseb)10 times decreasec)16 times decreased)16 times increaseCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for Class 11 2023 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for In an adiabatic process gas is reduced to quarter of its volume. What would happen to its pressure? Given ratio of specific heats γ= 2a)10 times increaseb)10 times decreasec)16 times decreased)16 times increaseCorrect answer is option 'C'. Can you explain this answer?.
In an adiabatic process gas is reduced to quarter of its volume. What would happen to its pressure? Given ratio of specific heats γ= 2a)10 times increaseb)10 times decreasec)16 times decreased)16 times increaseCorrect answer is option 'C'. Can you explain this answer? for Class 11 2023 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about In an adiabatic process gas is reduced to quarter of its volume. What would happen to its pressure? Given ratio of specific heats γ= 2a)10 times increaseb)10 times decreasec)16 times decreased)16 times increaseCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for Class 11 2023 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for In an adiabatic process gas is reduced to quarter of its volume. What would happen to its pressure? Given ratio of specific heats γ= 2a)10 times increaseb)10 times decreasec)16 times decreased)16 times increaseCorrect answer is option 'C'. Can you explain this answer?.
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Correct Answer : CExplanation : The adiabatic condition is given by the relation between pressure volume and temperature volume as:(PV)γ = constantwhere, γ = Cp/Cv is ratio of the specific heatsThese relations suggest that an decrease in volume is associated with increase in temperatureATQP1(V1)γ = (P2V2)γ=> P1(1)2 = P2(4)2P1/P2 = 16
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