In an adiabatic process gas is reduced to qua...

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In an adiabatic process gas is reduced to quarter of its volume. What would happen to its pressure? Given ratio of specific heats γ= 2
a)10 times increas
e
b)10 times decrease
c)16 times decrease
d)16 times increase

Explanation : The adiabatic condition is given by the relation between pressure volume and temperature volume as:
(PV)γ = constant
where, γ = Cp/Cv is ratio of the specific heats
These relations suggest that an decrease in volume is associated with increase in temperature

ATQ
P1(V1)γ = (P2V2
=> P1(1)2 = P2(4)2
P1/P2 = 16

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In an adiabatic process gas is reduced to quarter of its volume. What would happen to its pressure? Given ratio of specific heats γ= 2a)10 times increaseb)10 times decreasec)16 times decreased)16 times increaseCorrect answer is option 'C'. Can you explain this answer?

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Dhenya Mehta,when you don^t know answer,please don^t be a Einstein,correct answer is D,everyone should report this question

In an adiabatic process gas is reduced to quarter of its volume. What would happen to its pressure? Given ratio of specific heats γ= 2a)10 times increaseb)10 times decreasec)16 times decreased)16 times increaseCorrect answer is option 'C'. Can you explain this answer?
Ya the crt answer is d

Answer should be d. Because we hav
P1/p2=1/16 so the answer will be d

In an adiabatic process gas is reduced to quarter of its volume. What would happen to its pressure? Given ratio of specific heats γ= 2a)10 times increaseb)10 times decreasec)16 times decreased)16 times increaseCorrect answer is option 'C'. Can you explain this answer?
P1/p2=1/16 so,
p1=p2/16 so correct answer is Ddecrease by 16

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