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In an adiabatic process gas is reduced to quarter of its volume. What would happen to its pressure? Given ratio of specific heats γ= 2
a)10 times increas
eb)10 times decrease
c)16 times decrease
d)16 times increase
Correct answer is option 'C'. Can you explain this answer?
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Verified Answer
In an adiabatic process gas is reduced to quarter of its volume. What ...
Correct Answer : C
Explanation : The adiabatic condition is given by the relation between pressure volume and temperature volume as:
(PV)γ = constant
where, γ = Cp/Cv is ratio of the specific heats
These relations suggest that an decrease in volume is associated with increase in temperature
ATQ
P1(V1)γ = (P2V2)γ
=> P1(1)2 = P2(4)2
P1/P2 = 16
Most Upvoted Answer
In an adiabatic process gas is reduced to quarter of its volume. What ...
Since the process is adiabatic, we can use the equation:
P1 * V1^γ = P2 * V2^γ
where P1 and V1 are the initial pressure and volume, P2 and V2 are the final pressure and volume, and γ is the ratio of specific heats.
Let's assume that the initial volume is V and the final volume is V/4. Plugging this into the equation above, we get:
P1 * V^γ = P2 * (V/4)^γ
Dividing both sides by V^γ, we get:
P1 = P2 * (1/4)^γ
Since (1/4)^γ is less than 1, we can see that the final pressure (P2) will be greater than the initial pressure (P1).
Therefore, the pressure of the gas would increase when its volume is reduced to a quarter of its initial volume in an adiabatic process.
P1 * V1^γ = P2 * V2^γ
where P1 and V1 are the initial pressure and volume, P2 and V2 are the final pressure and volume, and γ is the ratio of specific heats.
Let's assume that the initial volume is V and the final volume is V/4. Plugging this into the equation above, we get:
P1 * V^γ = P2 * (V/4)^γ
Dividing both sides by V^γ, we get:
P1 = P2 * (1/4)^γ
Since (1/4)^γ is less than 1, we can see that the final pressure (P2) will be greater than the initial pressure (P1).
Therefore, the pressure of the gas would increase when its volume is reduced to a quarter of its initial volume in an adiabatic process.
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Community Answer
In an adiabatic process gas is reduced to quarter of its volume. What ...
Dhenya Mehta,when you don^t know answer,please don^t be a Einstein,correct answer is D,everyone should report this question
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In an adiabatic process gas is reduced to quarter of its volume. What would happen to its pressure? Given ratio of specific heats γ= 2a)10 times increaseb)10 times decreasec)16 times decreased)16 times increaseCorrect answer is option 'C'. Can you explain this answer?
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