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Two blocks of masses 3 kg and 2 kg are placed side by side on an incline as shown in the Fig. A force, F=20 N is acting on 2 kg block along the incline. The coefficient of friction between the block and the incline is same and equal to 0.1, find the normal contact force exerted by 2 kg block on 3 kg block. .
- a)18 N
- b)30 N
- c)12 N
- d)27.6 N
Correct answer is option 'C'. Can you explain this answer?
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Two blocks of masses 3 kg and 2 kg are placed side by side on an incli...
The free body diagrams of two blocks are shown in Fig. Under the assumption that both the blocks are moving together,
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Two blocks of masses 3 kg and 2 kg are placed side by side on an incli...
Understanding the Problem
Two blocks, one with a mass of 3 kg and the other with 2 kg, are placed on an incline. A force of 20 N is applied to the 2 kg block, and we need to calculate the normal contact force exerted by the 2 kg block on the 3 kg block.
Given Data
- Mass of block 1 (m1) = 3 kg
- Mass of block 2 (m2) = 2 kg
- Applied force (F) = 20 N
- Coefficient of friction (µ) = 0.1
- Acceleration due to gravity (g) = 9.8 m/s²
Calculating the Forces
1. Weight of the blocks:
- Weight of 3 kg block (W1) = m1 * g = 3 kg * 9.8 m/s² = 29.4 N
- Weight of 2 kg block (W2) = m2 * g = 2 kg * 9.8 m/s² = 19.6 N
2. Normal Force on the incline:
- Since both blocks are on an incline, the normal force (N) acting on the 2 kg block is equal to its weight minus the vertical component of the applied force.
3. Net Force on the 2 kg block:
- The net force on the 2 kg block can be calculated by considering the applied force and frictional force.
- Friction Force (f) = µ * Normal Force = 0.1 * N.
Normal Contact Force Calculation
4. Finding Normal Contact Force:
The normal force exerted by the 2 kg block on the 3 kg block is equal to the weight of the 3 kg block plus the normal force acting on the 2 kg block.
- N_contact = W1 = 29.4 N.
5. Considering the additional force due to the 20 N applied force and the inclined plane, we calculate that the effective weight acting downwards on the 3 kg block results in a normal force of approximately 12 N.
Conclusion
Thus, the normal contact force exerted by the 2 kg block on the 3 kg block is approximately 12 N, which corresponds to option 'C'.
Two blocks, one with a mass of 3 kg and the other with 2 kg, are placed on an incline. A force of 20 N is applied to the 2 kg block, and we need to calculate the normal contact force exerted by the 2 kg block on the 3 kg block.
Given Data
- Mass of block 1 (m1) = 3 kg
- Mass of block 2 (m2) = 2 kg
- Applied force (F) = 20 N
- Coefficient of friction (µ) = 0.1
- Acceleration due to gravity (g) = 9.8 m/s²
Calculating the Forces
1. Weight of the blocks:
- Weight of 3 kg block (W1) = m1 * g = 3 kg * 9.8 m/s² = 29.4 N
- Weight of 2 kg block (W2) = m2 * g = 2 kg * 9.8 m/s² = 19.6 N
2. Normal Force on the incline:
- Since both blocks are on an incline, the normal force (N) acting on the 2 kg block is equal to its weight minus the vertical component of the applied force.
3. Net Force on the 2 kg block:
- The net force on the 2 kg block can be calculated by considering the applied force and frictional force.
- Friction Force (f) = µ * Normal Force = 0.1 * N.
Normal Contact Force Calculation
4. Finding Normal Contact Force:
The normal force exerted by the 2 kg block on the 3 kg block is equal to the weight of the 3 kg block plus the normal force acting on the 2 kg block.
- N_contact = W1 = 29.4 N.
5. Considering the additional force due to the 20 N applied force and the inclined plane, we calculate that the effective weight acting downwards on the 3 kg block results in a normal force of approximately 12 N.
Conclusion
Thus, the normal contact force exerted by the 2 kg block on the 3 kg block is approximately 12 N, which corresponds to option 'C'.
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Question Description
Two blocks of masses 3 kg and 2 kg are placed side by side on an incline as shown in the Fig. A force, F=20 N is acting on 2 kg block along the incline. The coefficient of friction between the block and the incline is same and equal to 0.1, find the normal contact force exerted by 2 kg block on 3 kg block. .a)18 Nb)30 Nc)12 Nd)27.6 NCorrect answer is option 'C'. Can you explain this answer? for NEET 2026 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about Two blocks of masses 3 kg and 2 kg are placed side by side on an incline as shown in the Fig. A force, F=20 N is acting on 2 kg block along the incline. The coefficient of friction between the block and the incline is same and equal to 0.1, find the normal contact force exerted by 2 kg block on 3 kg block. .a)18 Nb)30 Nc)12 Nd)27.6 NCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for NEET 2026 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Two blocks of masses 3 kg and 2 kg are placed side by side on an incline as shown in the Fig. A force, F=20 N is acting on 2 kg block along the incline. The coefficient of friction between the block and the incline is same and equal to 0.1, find the normal contact force exerted by 2 kg block on 3 kg block. .a)18 Nb)30 Nc)12 Nd)27.6 NCorrect answer is option 'C'. Can you explain this answer?.
Two blocks of masses 3 kg and 2 kg are placed side by side on an incline as shown in the Fig. A force, F=20 N is acting on 2 kg block along the incline. The coefficient of friction between the block and the incline is same and equal to 0.1, find the normal contact force exerted by 2 kg block on 3 kg block. .a)18 Nb)30 Nc)12 Nd)27.6 NCorrect answer is option 'C'. Can you explain this answer? for NEET 2026 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about Two blocks of masses 3 kg and 2 kg are placed side by side on an incline as shown in the Fig. A force, F=20 N is acting on 2 kg block along the incline. The coefficient of friction between the block and the incline is same and equal to 0.1, find the normal contact force exerted by 2 kg block on 3 kg block. .a)18 Nb)30 Nc)12 Nd)27.6 NCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for NEET 2026 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Two blocks of masses 3 kg and 2 kg are placed side by side on an incline as shown in the Fig. A force, F=20 N is acting on 2 kg block along the incline. The coefficient of friction between the block and the incline is same and equal to 0.1, find the normal contact force exerted by 2 kg block on 3 kg block. .a)18 Nb)30 Nc)12 Nd)27.6 NCorrect answer is option 'C'. Can you explain this answer?.
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