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Which of the following arrangements does not represent the correct order of the property stated against it?
[AIEEE 2013]
- a)Se < Ti < Cr < Mn : number of oxidation states.
- b)V2+ < Cr2+ < Mn2+ < Fe2+ : Paramagnetic behaviour.
- c)Ni2+< Co2+< Fe2+ < Mn2+ : ionic size
- d)Co3+ < Fe3+ < Cr3+ < Sc3+ stability in aqueous solution.
Correct answer is option 'B'. Can you explain this answer?
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Verified Answer
Which of the following arrangements does not represent the correct ord...
A) V^2+<Cr^2+<Mn^2+<Fe^2+ : paramagnetic behaviour
Electronic configuration of V^2+ = 3d^3 ; n=3
Electronic configuration of Cr^2+=3d^4 ; n=4
Electronic configuration of Mn^2+=3d^5 ; n=5
Electronic configuration of Fe^2+=3d^6 ; n=4
Here, Mn2+ has maximum number of unpaired electrons and so its most paramagentic. Therefore the correct order is :
V^2+<Cr^2+<Mn^2+
B) Ni^2+<Co^2+<Fe^2+<Mn^2+ : Ionic size
We know for the same oxidation state, the ionic radii generally decrease with increase in nuclear charge and the nuclear charge increase as we move across a period. Therefore, the given order is correct.
C) Co^3+<Fe^3+<Cr^3+<Sc^3+ : Stability in aqueous solution
The lower the electrode potential, i.e. more negative the standard reduction potential of the electrode, the more stable is the transition metal in aqueous solution. The value becomes less negative across the series. Therefore, the given order is correct.
D)Sc<Ti<Cr<Mn : number of oxidation states
The given order is correct as Mn shows maximum number of oxidation states i.e. upto +7 (due to its configuration 3d^5 4s^2 it can have maximum oxidation states). Sc on the other hand shows least oxidation state.
Therefore, (B) doesnot show correct order of property.
Most Upvoted Answer
Which of the following arrangements does not represent the correct ord...
Incorrect Order of Paramagnetic Behavior:
The correct answer is option B, which does not represent the correct order of the property stated against it. Let's break down why this arrangement is incorrect:
Explanation:
- V2+ < Cr2+ < Mn2+ < Fe2+: Paramagnetic behavior
- Paramagnetic behavior is exhibited by species that have unpaired electrons. In this case, the arrangement suggests that Fe2+ has more unpaired electrons and should exhibit stronger paramagnetic behavior compared to V2+, Cr2+, and Mn2+. However, this is incorrect as Fe2+ has a completely filled d orbital (d6 configuration) and is diamagnetic, not paramagnetic.
- The correct order of paramagnetic behavior should be V2+ < Cr2+ < Mn2+ < Fe2+.
Therefore, option B is the incorrect arrangement as it does not accurately represent the paramagnetic behavior of the given ions.
The correct answer is option B, which does not represent the correct order of the property stated against it. Let's break down why this arrangement is incorrect:
Explanation:
- V2+ < Cr2+ < Mn2+ < Fe2+: Paramagnetic behavior
- Paramagnetic behavior is exhibited by species that have unpaired electrons. In this case, the arrangement suggests that Fe2+ has more unpaired electrons and should exhibit stronger paramagnetic behavior compared to V2+, Cr2+, and Mn2+. However, this is incorrect as Fe2+ has a completely filled d orbital (d6 configuration) and is diamagnetic, not paramagnetic.
- The correct order of paramagnetic behavior should be V2+ < Cr2+ < Mn2+ < Fe2+.
Therefore, option B is the incorrect arrangement as it does not accurately represent the paramagnetic behavior of the given ions.
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Community Answer
Which of the following arrangements does not represent the correct ord...
B) V2+<Cr2+<Mn2+<Fe2+ : paramagnetic behaviour
Electronic configuration of V2+ = 3d3 ; n=3
Electronic configuration of Cr2+=3d4 ; n=4
Electronic configuration of Mn2+=3d5 ; n=5
Electronic configuration of Fe2+=3d6 ; n=4
Here, Mn2+ has maximum number of unpaired electrons and so its most paramagentic. Therefore the correct order is :
V2+<Cr2+<Fe2+<Mn2+
C) Ni2+<Co2+<Fe2+<Mn2+ : Ionic size
We know for the same oxidation state, the ionic radii generally decrease with increase in nuclear charge and the nuclear charge increase as we move across a period. Therefore, the given order is correct.
D) Co3+<Fe3+<Cr3+<Sc3+ : Stability in aqueous solution
The lower the electrode potential, i.e. more negative the standard reduction potential of the electrode, the more stable is the transition metal in aqueous solution. The value becomes less negative across the series. Therefore, the given order is correct.
A)Sc<Ti<Cr<Mn : number of oxidation states
The given order is correct as Mn shows maximum number of oxidation states i.e. upto +7 (due to its configuration 3d5 4s2 it can have maximum oxidation states). Sc on the other hand shows least oxidation state.
Therefore, (B) doesnot show correct order of property.
Electronic configuration of V2+ = 3d3 ; n=3
Electronic configuration of Cr2+=3d4 ; n=4
Electronic configuration of Mn2+=3d5 ; n=5
Electronic configuration of Fe2+=3d6 ; n=4
Here, Mn2+ has maximum number of unpaired electrons and so its most paramagentic. Therefore the correct order is :
V2+<Cr2+<Fe2+<Mn2+
C) Ni2+<Co2+<Fe2+<Mn2+ : Ionic size
We know for the same oxidation state, the ionic radii generally decrease with increase in nuclear charge and the nuclear charge increase as we move across a period. Therefore, the given order is correct.
D) Co3+<Fe3+<Cr3+<Sc3+ : Stability in aqueous solution
The lower the electrode potential, i.e. more negative the standard reduction potential of the electrode, the more stable is the transition metal in aqueous solution. The value becomes less negative across the series. Therefore, the given order is correct.
A)Sc<Ti<Cr<Mn : number of oxidation states
The given order is correct as Mn shows maximum number of oxidation states i.e. upto +7 (due to its configuration 3d5 4s2 it can have maximum oxidation states). Sc on the other hand shows least oxidation state.
Therefore, (B) doesnot show correct order of property.
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Which of the following arrangements does not represent the correct order of the property stated against it?[AIEEE 2013]a)Se < Ti < Cr < Mn : number of oxidation states.b)V2+< Cr2+< Mn2+< Fe2+: Paramagnetic behaviour.c)Ni2+< Co2+< Fe2+< Mn2+: ionic sized)Co3+< Fe3+< Cr3+< Sc3+stability in aqueous solution.Correct answer is option 'B'. Can you explain this answer?
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Which of the following arrangements does not represent the correct order of the property stated against it?[AIEEE 2013]a)Se < Ti < Cr < Mn : number of oxidation states.b)V2+< Cr2+< Mn2+< Fe2+: Paramagnetic behaviour.c)Ni2+< Co2+< Fe2+< Mn2+: ionic sized)Co3+< Fe3+< Cr3+< Sc3+stability in aqueous solution.Correct answer is option 'B'. Can you explain this answer? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about Which of the following arrangements does not represent the correct order of the property stated against it?[AIEEE 2013]a)Se < Ti < Cr < Mn : number of oxidation states.b)V2+< Cr2+< Mn2+< Fe2+: Paramagnetic behaviour.c)Ni2+< Co2+< Fe2+< Mn2+: ionic sized)Co3+< Fe3+< Cr3+< Sc3+stability in aqueous solution.Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Which of the following arrangements does not represent the correct order of the property stated against it?[AIEEE 2013]a)Se < Ti < Cr < Mn : number of oxidation states.b)V2+< Cr2+< Mn2+< Fe2+: Paramagnetic behaviour.c)Ni2+< Co2+< Fe2+< Mn2+: ionic sized)Co3+< Fe3+< Cr3+< Sc3+stability in aqueous solution.Correct answer is option 'B'. Can you explain this answer?.
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ample number of questions to practice Which of the following arrangements does not represent the correct order of the property stated against it?[AIEEE 2013]a)Se < Ti < Cr < Mn : number of oxidation states.b)V2+< Cr2+< Mn2+< Fe2+: Paramagnetic behaviour.c)Ni2+< Co2+< Fe2+< Mn2+: ionic sized)Co3+< Fe3+< Cr3+< Sc3+stability in aqueous solution.Correct answer is option 'B'. Can you explain this answer? tests, examples and also practice Class 11 tests.
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