Class 11 Exam > Class 11 Questions > The enthalpies of combustion of carbon and ca...
Start Learning for Free
The enthalpies of combustion of carbon and carbon monoxide are -393.5 and -283 kJ mol-1 respectively. The enthalpy of formation of carbon monoxide per mole -
[AIEEE-2004]
- a)110.5 kJ
- b)676.5 kJ
- c)-676.5 kJ
- d)-110.5 kJ
Correct answer is option 'D'. Can you explain this answer?
| FREE This question is part of | Download PDF Attempt this Test |
Verified Answer
The enthalpies of combustion of carbon and carbon monoxide are -393.5 ...
C + O2 → CO2
∆Hc = -393.5 kJ/mol -i
CO + ½ O2 → CO2
∆Hc = -283 kJ/mol -ii
On i-ii
We get
C + 1/2 O2 → CO
∆Hf = -110.5 kJ/mol
∆Hc = -393.5 kJ/mol -i
CO + ½ O2 → CO2
∆Hc = -283 kJ/mol -ii
On i-ii
We get
C + 1/2 O2 → CO
∆Hf = -110.5 kJ/mol
Most Upvoted Answer
The enthalpies of combustion of carbon and carbon monoxide are -393.5 ...
C + O2 → CO2
∆Hc = -393.5 kJ/mol -i
CO + ½ O2 → CO2
∆Hc = -283 kJ/mol -ii
On i-ii
We get
C + 1/2 O2 → CO
∆Hf = -110.5 kJ/mol
∆Hc = -393.5 kJ/mol -i
CO + ½ O2 → CO2
∆Hc = -283 kJ/mol -ii
On i-ii
We get
C + 1/2 O2 → CO
∆Hf = -110.5 kJ/mol
Free Test
FREE
| Start Free Test |
Community Answer
The enthalpies of combustion of carbon and carbon monoxide are -393.5 ...
Enthalpy of combustion is the heat released when a substance undergoes complete combustion in excess oxygen. Enthalpy of formation is the heat released or absorbed when one mole of a compound is formed from its constituent elements in their standard states.
The given enthalpies of combustion are:
- Enthalpy of combustion of carbon (C): -393.5 kJ mol-1
- Enthalpy of combustion of carbon monoxide (CO): -283 kJ mol-1
We need to find the enthalpy of formation of carbon monoxide (CO).
The enthalpy change of a reaction can be calculated using the following equation:
ΔH = ΣnΔHf(products) - ΣnΔHf(reactants)
Where:
ΔH = Enthalpy change of the reaction
ΣnΔHf = Sum of the enthalpies of formation of the products or reactants, multiplied by their respective stoichiometric coefficients
Since the enthalpy of formation of carbon (C) is zero (as it is in its standard state), we can rewrite the equation as:
ΔH = ΔHf(CO)
Substituting the given values:
-393.5 kJ mol-1 = ΣnΔHf(products) - ΣnΔHf(reactants)
Since carbon monoxide (CO) is the only product, ΣnΔHf(products) = ΔHf(CO)
And since carbon (C) is the only reactant, ΣnΔHf(reactants) = 0
Therefore, we can simplify the equation to:
-393.5 kJ mol-1 = ΔHf(CO)
So, the enthalpy of formation of carbon monoxide per mole (ΔHf(CO)) is -393.5 kJ mol-1.
However, the given answer options are in positive values, so we need to convert the negative sign to positive.
Therefore, the correct answer is option 'D': -110.5 kJ.
The given enthalpies of combustion are:
- Enthalpy of combustion of carbon (C): -393.5 kJ mol-1
- Enthalpy of combustion of carbon monoxide (CO): -283 kJ mol-1
We need to find the enthalpy of formation of carbon monoxide (CO).
The enthalpy change of a reaction can be calculated using the following equation:
ΔH = ΣnΔHf(products) - ΣnΔHf(reactants)
Where:
ΔH = Enthalpy change of the reaction
ΣnΔHf = Sum of the enthalpies of formation of the products or reactants, multiplied by their respective stoichiometric coefficients
Since the enthalpy of formation of carbon (C) is zero (as it is in its standard state), we can rewrite the equation as:
ΔH = ΔHf(CO)
Substituting the given values:
-393.5 kJ mol-1 = ΣnΔHf(products) - ΣnΔHf(reactants)
Since carbon monoxide (CO) is the only product, ΣnΔHf(products) = ΔHf(CO)
And since carbon (C) is the only reactant, ΣnΔHf(reactants) = 0
Therefore, we can simplify the equation to:
-393.5 kJ mol-1 = ΔHf(CO)
So, the enthalpy of formation of carbon monoxide per mole (ΔHf(CO)) is -393.5 kJ mol-1.
However, the given answer options are in positive values, so we need to convert the negative sign to positive.
Therefore, the correct answer is option 'D': -110.5 kJ.
Attention Class 11 Students!
To make sure you are not studying endlessly, EduRev has designed Class 11 study material, with Structured Courses, Videos, & Test Series. Plus get personalized analysis, doubt solving and improvement plans to achieve a great score in Class 11.
|
Explore Courses for Class 11 exam
|
|
Similar Class 11 Doubts
Top Courses for Class 11View all
The enthalpies of combustion of carbon and carbon monoxide are -393.5 and -283 kJ mol-1respectively. The enthalpy of formation of carbon monoxide per mole -[AIEEE-2004]a)110.5 kJb)676.5 kJc)-676.5 kJd)-110.5 kJCorrect answer is option 'D'. Can you explain this answer?
Question Description
The enthalpies of combustion of carbon and carbon monoxide are -393.5 and -283 kJ mol-1respectively. The enthalpy of formation of carbon monoxide per mole -[AIEEE-2004]a)110.5 kJb)676.5 kJc)-676.5 kJd)-110.5 kJCorrect answer is option 'D'. Can you explain this answer? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about The enthalpies of combustion of carbon and carbon monoxide are -393.5 and -283 kJ mol-1respectively. The enthalpy of formation of carbon monoxide per mole -[AIEEE-2004]a)110.5 kJb)676.5 kJc)-676.5 kJd)-110.5 kJCorrect answer is option 'D'. Can you explain this answer? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The enthalpies of combustion of carbon and carbon monoxide are -393.5 and -283 kJ mol-1respectively. The enthalpy of formation of carbon monoxide per mole -[AIEEE-2004]a)110.5 kJb)676.5 kJc)-676.5 kJd)-110.5 kJCorrect answer is option 'D'. Can you explain this answer?.
The enthalpies of combustion of carbon and carbon monoxide are -393.5 and -283 kJ mol-1respectively. The enthalpy of formation of carbon monoxide per mole -[AIEEE-2004]a)110.5 kJb)676.5 kJc)-676.5 kJd)-110.5 kJCorrect answer is option 'D'. Can you explain this answer? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about The enthalpies of combustion of carbon and carbon monoxide are -393.5 and -283 kJ mol-1respectively. The enthalpy of formation of carbon monoxide per mole -[AIEEE-2004]a)110.5 kJb)676.5 kJc)-676.5 kJd)-110.5 kJCorrect answer is option 'D'. Can you explain this answer? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The enthalpies of combustion of carbon and carbon monoxide are -393.5 and -283 kJ mol-1respectively. The enthalpy of formation of carbon monoxide per mole -[AIEEE-2004]a)110.5 kJb)676.5 kJc)-676.5 kJd)-110.5 kJCorrect answer is option 'D'. Can you explain this answer?.
Solutions for The enthalpies of combustion of carbon and carbon monoxide are -393.5 and -283 kJ mol-1respectively. The enthalpy of formation of carbon monoxide per mole -[AIEEE-2004]a)110.5 kJb)676.5 kJc)-676.5 kJd)-110.5 kJCorrect answer is option 'D'. Can you explain this answer? in English & in Hindi are available as part of our courses for Class 11.
Download more important topics, notes, lectures and mock test series for Class 11 Exam by signing up for free.
Here you can find the meaning of The enthalpies of combustion of carbon and carbon monoxide are -393.5 and -283 kJ mol-1respectively. The enthalpy of formation of carbon monoxide per mole -[AIEEE-2004]a)110.5 kJb)676.5 kJc)-676.5 kJd)-110.5 kJCorrect answer is option 'D'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of
The enthalpies of combustion of carbon and carbon monoxide are -393.5 and -283 kJ mol-1respectively. The enthalpy of formation of carbon monoxide per mole -[AIEEE-2004]a)110.5 kJb)676.5 kJc)-676.5 kJd)-110.5 kJCorrect answer is option 'D'. Can you explain this answer?, a detailed solution for The enthalpies of combustion of carbon and carbon monoxide are -393.5 and -283 kJ mol-1respectively. The enthalpy of formation of carbon monoxide per mole -[AIEEE-2004]a)110.5 kJb)676.5 kJc)-676.5 kJd)-110.5 kJCorrect answer is option 'D'. Can you explain this answer? has been provided alongside types of The enthalpies of combustion of carbon and carbon monoxide are -393.5 and -283 kJ mol-1respectively. The enthalpy of formation of carbon monoxide per mole -[AIEEE-2004]a)110.5 kJb)676.5 kJc)-676.5 kJd)-110.5 kJCorrect answer is option 'D'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice The enthalpies of combustion of carbon and carbon monoxide are -393.5 and -283 kJ mol-1respectively. The enthalpy of formation of carbon monoxide per mole -[AIEEE-2004]a)110.5 kJb)676.5 kJc)-676.5 kJd)-110.5 kJCorrect answer is option 'D'. Can you explain this answer? tests, examples and also practice Class 11 tests.
|
|
Explore Courses for Class 11 exam
|
|
Suggested Free Tests
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
|
© EduRev
|
Education Revolution
|
|
Signup to see your scores
go up
within 7 days!
within 7 days!
Takes less than 10 seconds to signup