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If x+y+z=0 then prove that xcube+ycube+zcube=3xyz?
Most Upvoted Answer
If x+y+z=0 then prove that xcube+ycube+zcube=3xyz?
Very easy as X+y+z=0X+y=-zX cube +y cube +z cube=3xyz(X+y)cube-3xy(x+y)+z cube =3xyz(-z)cube -3xy(-z)+zcube =3xyz3xyz=3xyz prooved...
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If x+y+z=0 then prove that xcube+ycube+zcube=3xyz?
X+y+z=0 X+y=-z.........(1) cubing both sides (X+y)^3=(-z)^3= x^3+y^3+3xy(X+y)=-z^3 x^3+y^3+3xy(-z)=-z^3........using(1) x^3+y^3+z^3=3xyz
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If x+y+z=0 then prove that xcube+ycube+zcube=3xyz?
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