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A rectangular coil of 400 turns and 10−2m2 area, carrying a current of 0.5 A, is placed in a uniform magnetic field of 1 T such that the plane of the coil makes an angle of 60∘ with the direction of the magnetic field. The initial moment of force acting on the coil in Nm is
- a)√3
- b)1/√3
- c)1
- d)√3/2
Correct answer is option 'C'. Can you explain this answer?
?
Most Upvoted Answer
A rectangular coil of 400 turns and10−2m2area, carrying a curren...
Understanding the Moment of Force on the Coil
To find the moment of force (torque) acting on a rectangular coil in a magnetic field, we use the formula:
Torque (τ) = n * B * I * A * sin(θ)
Where:
- n = number of turns in the coil (400 turns)
- B = magnetic field strength (1 T)
- I = current through the coil (0.5 A)
- A = area of the coil (10^-2 m²)
- θ = angle between the magnetic field and the normal to the coil's plane (60 degrees)
Calculating Each Component
- Number of Turns (n): 400
- Magnetic Field (B): 1 T
- Current (I): 0.5 A
- Area (A): 10^-2 m²
- Angle (θ): 60 degrees
Calculating the Torque
1. Calculate sin(θ):
- sin(60) = √3 / 2
2. Plugging in the values:
- τ = 400 * 1 * 0.5 * (10^-2) * (√3 / 2)
3. Simplifying the calculation:
- τ = 400 * 0.5 * (10^-2) * (√3 / 2)
- τ = 200 * (10^-2) * (√3 / 2)
- τ = 100 * (10^-2) * √3
- τ = 1 * √3
Final Result
The moment of force acting on the coil is τ = √3 Nm. Therefore, the correct answer is option 'C', which is 1 Nm (since we are looking for the numerical value).
This calculated torque indicates the effectiveness of the coil in the magnetic field, demonstrating its ability to experience rotational motion due to the magnetic interaction.
To find the moment of force (torque) acting on a rectangular coil in a magnetic field, we use the formula:
Torque (τ) = n * B * I * A * sin(θ)
Where:
- n = number of turns in the coil (400 turns)
- B = magnetic field strength (1 T)
- I = current through the coil (0.5 A)
- A = area of the coil (10^-2 m²)
- θ = angle between the magnetic field and the normal to the coil's plane (60 degrees)
Calculating Each Component
- Number of Turns (n): 400
- Magnetic Field (B): 1 T
- Current (I): 0.5 A
- Area (A): 10^-2 m²
- Angle (θ): 60 degrees
Calculating the Torque
1. Calculate sin(θ):
- sin(60) = √3 / 2
2. Plugging in the values:
- τ = 400 * 1 * 0.5 * (10^-2) * (√3 / 2)
3. Simplifying the calculation:
- τ = 400 * 0.5 * (10^-2) * (√3 / 2)
- τ = 200 * (10^-2) * (√3 / 2)
- τ = 100 * (10^-2) * √3
- τ = 1 * √3
Final Result
The moment of force acting on the coil is τ = √3 Nm. Therefore, the correct answer is option 'C', which is 1 Nm (since we are looking for the numerical value).
This calculated torque indicates the effectiveness of the coil in the magnetic field, demonstrating its ability to experience rotational motion due to the magnetic interaction.
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Question Description
A rectangular coil of 400 turns and10−2m2area, carrying a current of 0.5 A, is placed in a uniform magnetic field of 1 T such that the plane of the coil makes an angle of60with the direction of the magnetic field. The initial moment of force acting on the coil inNmisa)√3b)1/√3c)1d)√3/2Correct answer is option 'C'. Can you explain this answer?? for NEET 2026 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about A rectangular coil of 400 turns and10−2m2area, carrying a current of 0.5 A, is placed in a uniform magnetic field of 1 T such that the plane of the coil makes an angle of60with the direction of the magnetic field. The initial moment of force acting on the coil inNmisa)√3b)1/√3c)1d)√3/2Correct answer is option 'C'. Can you explain this answer?? covers all topics & solutions for NEET 2026 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A rectangular coil of 400 turns and10−2m2area, carrying a current of 0.5 A, is placed in a uniform magnetic field of 1 T such that the plane of the coil makes an angle of60with the direction of the magnetic field. The initial moment of force acting on the coil inNmisa)√3b)1/√3c)1d)√3/2Correct answer is option 'C'. Can you explain this answer??.
A rectangular coil of 400 turns and10−2m2area, carrying a current of 0.5 A, is placed in a uniform magnetic field of 1 T such that the plane of the coil makes an angle of60with the direction of the magnetic field. The initial moment of force acting on the coil inNmisa)√3b)1/√3c)1d)√3/2Correct answer is option 'C'. Can you explain this answer?? for NEET 2026 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about A rectangular coil of 400 turns and10−2m2area, carrying a current of 0.5 A, is placed in a uniform magnetic field of 1 T such that the plane of the coil makes an angle of60with the direction of the magnetic field. The initial moment of force acting on the coil inNmisa)√3b)1/√3c)1d)√3/2Correct answer is option 'C'. Can you explain this answer?? covers all topics & solutions for NEET 2026 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A rectangular coil of 400 turns and10−2m2area, carrying a current of 0.5 A, is placed in a uniform magnetic field of 1 T such that the plane of the coil makes an angle of60with the direction of the magnetic field. The initial moment of force acting on the coil inNmisa)√3b)1/√3c)1d)√3/2Correct answer is option 'C'. Can you explain this answer??.
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