Calculation of Minimum Molecular Weight of Peroxidase Anhydrous Enzyme

Given:
Percentage of Se in peroxidase anhydrous enzyme = 0.5% by weight
Atomic weight of Se = 78.4

Formula:
Percentage by weight = (Weight of element / Molecular weight of compound) x 100

Calculation:
Let us assume the molecular weight of peroxidase anhydrous enzyme as "x"
Then, the weight of Se in peroxidase anhydrous enzyme = 0.5% of x
Therefore, Weight of Se = (0.5/100) x x = x/200

Using the formula mentioned above, we can write

Percentage by weight of Se = (Weight of Se / Molecular weight of peroxidase anhydrous enzyme) x 100
0.5 = [(x/200) / x] x 100
0.5 = 1/200 x 100
x = 20000

Therefore, the minimum molecular weight of peroxidase anhydrous enzyme is 20000.

Explanation:
Peroxidase anhydrous enzyme is an enzyme that contains selenium (Se) as one of its elements. The percentage of Se in peroxidase anhydrous enzyme is given as 0.5% by weight. Using this information, we can calculate the minimum molecular weight of peroxidase anhydrous enzyme. The formula for percentage by weight is used to find the weight of Se in peroxidase anhydrous enzyme. By assuming the molecular weight of peroxidase anhydrous enzyme as "x", we can calculate the molecular weight of peroxidase anhydrous enzyme. The final answer is obtained as 20000, which is the minimum molecular weight of peroxidase anhydrous enzyme.