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A Capacitor of Capacitance C is charged to a p.d V from a cell and disconnected from it. A charge +Q is now given to its positive plate. The P.d across the capacitor is now?
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A Capacitor of Capacitance C is charged to a p.d V from a cell and dis...
Capacitance of capacitor is c ,p.d.is v
consider initial charge be Q′ charge given to plate Q
total charge on+ve plate will be Q′+Q
potential difference now= (E'+E)d
E= electric field due to positive plate= Q+Q′/2εA
E'= electric field due to negetive plate=Q/2εA
so potential difference=(E+E')d
on solving we get V'=Q/2C+V
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A Capacitor of Capacitance C is charged to a p.d V from a cell and disconnected from it. A charge +Q is now given to its positive plate. The P.d across the capacitor is now?
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A Capacitor of Capacitance C is charged to a p.d V from a cell and disconnected from it. A charge +Q is now given to its positive plate. The P.d across the capacitor is now? for Class 12 2024 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about A Capacitor of Capacitance C is charged to a p.d V from a cell and disconnected from it. A charge +Q is now given to its positive plate. The P.d across the capacitor is now? covers all topics & solutions for Class 12 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A Capacitor of Capacitance C is charged to a p.d V from a cell and disconnected from it. A charge +Q is now given to its positive plate. The P.d across the capacitor is now?.
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