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If C the velocity of light, h Planck's constant and G gravitational constant are taken as fundamental quantities, then the dimensional formula of mass is
  • a)
    h−1/2G1/2C0
  • b)
    h1/2C1/2G−1/2
  • c)
    h−1/2C1/2G−1/2
  • d)
    h−1/2C−1/2G−1/2
Correct answer is option 'B'. Can you explain this answer?
Most Upvoted Answer
If C the velocity of light, h Planck's constant and G gravitational co...
Understanding the Problem
To derive the dimensional formula of mass using C (velocity of light), h (Planck's constant), and G (gravitational constant), we start with their respective dimensions:
- C (Velocity of Light): [C] = L^1 T^-1
- h (Planck's Constant): [h] = M^1 L^2 T^-1
- G (Gravitational Constant): [G] = M^-1 L^3 T^-2
Dimensional Analysis
We want to express mass (M) in terms of C, h, and G. Let's assume the dimensional formula of mass is given by:
M = h^a C^b G^c
This translates to:
M^1 = (M^1 L^2 T^-1)^a (L^1 T^-1)^b (M^-1 L^3 T^-2)^c
Equating Dimensions
Now, we can equate the dimensions of mass, length, and time on both sides:
1. For Mass (M): 1 = a - c
2. For Length (L): 0 = 2a + b + 3c
3. For Time (T): 0 = -a - b - 2c
Solving the Equations
From the first equation, we have:
c = a - 1
Substituting c in the second and third equations gives us a system of equations. After solving these equations, we find:
- a = 1/2
- b = 1/2
- c = -1/2
Final Result
Substituting back into our assumed formula gives us:
M = h^(1/2) C^(1/2) G^(-1/2)
Thus, the correct answer is option 'b':
Answer: h^(1/2) C^(1/2) G^(-1/2)
Free Test
Community Answer
If C the velocity of light, h Planck's constant and G gravitational co...
Let,


Comparing the coefficients M,L,T, of both sides we get
b−c=1
a + 2b + 3c = 0
−(a + b + 2c) = 0
Solve the Eqs. (ii), (iii) and (iv), we get

So,
M=h1/2C1/2G−1/2
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Question Description
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