JEE Exam > JEE Questions > A particle starts with an initial velocity 2....
Start Learning for Free
A particle starts with an initial velocity 2.5m/s along the +ve x axis and it accelerates uniformly at the rate 0.5m/ss. (a) find distance travelled by it in first two seconds. (b)How much time does it take to reach the velocity 7.5m/s (c)How much distance will it cover before reaching the velocity 7.5m/s?
Most Upvoted Answer
A particle starts with an initial velocity 2.5m/s along the +ve x axis...
Given:
Initial velocity (u) = 2.5 m/s
Acceleration (a) = 0.5 m/s²
(a) Distance traveled in the first two seconds:
We can use the kinematic equation to find the distance traveled by the particle in the first two seconds.
The kinematic equation is:
s = ut + 0.5at²
Substituting the given values:
s = (2.5 m/s)(2 s) + 0.5(0.5 m/s²)(2 s)²
s = 5 m + 0.5 m/s² * 4 s²
s = 5 m + 0.5 m/s² * 16 s²
s = 5 m + 8 m
s = 13 m
Therefore, the particle travels a distance of 13 meters in the first two seconds.
(b) Time taken to reach a velocity of 7.5 m/s:
We can use the equation of motion to find the time taken to reach a velocity of 7.5 m/s.
The equation of motion is:
v = u + at
Substituting the given values:
7.5 m/s = 2.5 m/s + 0.5 m/s² * t
Rearranging the equation to solve for t:
7.5 m/s - 2.5 m/s = 0.5 m/s² * t
5 m/s = 0.5 m/s² * t
t = 5 m/s / 0.5 m/s²
t = 10 s
Therefore, it takes 10 seconds for the particle to reach a velocity of 7.5 m/s.
(c) Distance covered before reaching a velocity of 7.5 m/s:
To find the distance covered before reaching a velocity of 7.5 m/s, we can use the equation of motion.
The equation of motion is:
v² = u² + 2as
Substituting the given values:
(7.5 m/s)² = (2.5 m/s)² + 2(0.5 m/s²)s
Simplifying the equation:
56.25 m²/s² = 6.25 m²/s² + 1 m/s² * s
56.25 m²/s² - 6.25 m²/s² = 1 m/s² * s
50 m²/s² = 1 m/s² * s
s = 50 m²/s² / 1 m/s²
s = 50 m
Therefore, the particle will cover a distance of 50 meters before reaching a velocity of 7.5 m/s.
In summary,
(a) The particle travels a distance of 13 meters in the first two seconds.
(b) It takes 10 seconds for the particle to reach a velocity of 7.5 m/s.
(c) The particle will cover a distance of 50 meters before reaching a velocity of 7.5 m/s.
Initial velocity (u) = 2.5 m/s
Acceleration (a) = 0.5 m/s²
(a) Distance traveled in the first two seconds:
We can use the kinematic equation to find the distance traveled by the particle in the first two seconds.
The kinematic equation is:
s = ut + 0.5at²
Substituting the given values:
s = (2.5 m/s)(2 s) + 0.5(0.5 m/s²)(2 s)²
s = 5 m + 0.5 m/s² * 4 s²
s = 5 m + 0.5 m/s² * 16 s²
s = 5 m + 8 m
s = 13 m
Therefore, the particle travels a distance of 13 meters in the first two seconds.
(b) Time taken to reach a velocity of 7.5 m/s:
We can use the equation of motion to find the time taken to reach a velocity of 7.5 m/s.
The equation of motion is:
v = u + at
Substituting the given values:
7.5 m/s = 2.5 m/s + 0.5 m/s² * t
Rearranging the equation to solve for t:
7.5 m/s - 2.5 m/s = 0.5 m/s² * t
5 m/s = 0.5 m/s² * t
t = 5 m/s / 0.5 m/s²
t = 10 s
Therefore, it takes 10 seconds for the particle to reach a velocity of 7.5 m/s.
(c) Distance covered before reaching a velocity of 7.5 m/s:
To find the distance covered before reaching a velocity of 7.5 m/s, we can use the equation of motion.
The equation of motion is:
v² = u² + 2as
Substituting the given values:
(7.5 m/s)² = (2.5 m/s)² + 2(0.5 m/s²)s
Simplifying the equation:
56.25 m²/s² = 6.25 m²/s² + 1 m/s² * s
56.25 m²/s² - 6.25 m²/s² = 1 m/s² * s
50 m²/s² = 1 m/s² * s
s = 50 m²/s² / 1 m/s²
s = 50 m
Therefore, the particle will cover a distance of 50 meters before reaching a velocity of 7.5 m/s.
In summary,
(a) The particle travels a distance of 13 meters in the first two seconds.
(b) It takes 10 seconds for the particle to reach a velocity of 7.5 m/s.
(c) The particle will cover a distance of 50 meters before reaching a velocity of 7.5 m/s.
Community Answer
A particle starts with an initial velocity 2.5m/s along the +ve x axis...
A) 6 meters b) 10 sec. c) 50 meters
Attention JEE Students!
To make sure you are not studying endlessly, EduRev has designed JEE study material, with Structured Courses, Videos, & Test Series. Plus get personalized analysis, doubt solving and improvement plans to achieve a great score in JEE.
|
Explore Courses for JEE exam
|
|
Similar JEE Doubts
Top Courses for JEEView all
A particle starts with an initial velocity 2.5m/s along the +ve x axis and it accelerates uniformly at the rate 0.5m/ss. (a) find distance travelled by it in first two seconds. (b)How much time does it take to reach the velocity 7.5m/s (c)How much distance will it cover before reaching the velocity 7.5m/s?
Question Description
A particle starts with an initial velocity 2.5m/s along the +ve x axis and it accelerates uniformly at the rate 0.5m/ss. (a) find distance travelled by it in first two seconds. (b)How much time does it take to reach the velocity 7.5m/s (c)How much distance will it cover before reaching the velocity 7.5m/s? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about A particle starts with an initial velocity 2.5m/s along the +ve x axis and it accelerates uniformly at the rate 0.5m/ss. (a) find distance travelled by it in first two seconds. (b)How much time does it take to reach the velocity 7.5m/s (c)How much distance will it cover before reaching the velocity 7.5m/s? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A particle starts with an initial velocity 2.5m/s along the +ve x axis and it accelerates uniformly at the rate 0.5m/ss. (a) find distance travelled by it in first two seconds. (b)How much time does it take to reach the velocity 7.5m/s (c)How much distance will it cover before reaching the velocity 7.5m/s?.
A particle starts with an initial velocity 2.5m/s along the +ve x axis and it accelerates uniformly at the rate 0.5m/ss. (a) find distance travelled by it in first two seconds. (b)How much time does it take to reach the velocity 7.5m/s (c)How much distance will it cover before reaching the velocity 7.5m/s? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about A particle starts with an initial velocity 2.5m/s along the +ve x axis and it accelerates uniformly at the rate 0.5m/ss. (a) find distance travelled by it in first two seconds. (b)How much time does it take to reach the velocity 7.5m/s (c)How much distance will it cover before reaching the velocity 7.5m/s? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A particle starts with an initial velocity 2.5m/s along the +ve x axis and it accelerates uniformly at the rate 0.5m/ss. (a) find distance travelled by it in first two seconds. (b)How much time does it take to reach the velocity 7.5m/s (c)How much distance will it cover before reaching the velocity 7.5m/s?.
Solutions for A particle starts with an initial velocity 2.5m/s along the +ve x axis and it accelerates uniformly at the rate 0.5m/ss. (a) find distance travelled by it in first two seconds. (b)How much time does it take to reach the velocity 7.5m/s (c)How much distance will it cover before reaching the velocity 7.5m/s? in English & in Hindi are available as part of our courses for JEE.
Download more important topics, notes, lectures and mock test series for JEE Exam by signing up for free.
Here you can find the meaning of A particle starts with an initial velocity 2.5m/s along the +ve x axis and it accelerates uniformly at the rate 0.5m/ss. (a) find distance travelled by it in first two seconds. (b)How much time does it take to reach the velocity 7.5m/s (c)How much distance will it cover before reaching the velocity 7.5m/s? defined & explained in the simplest way possible. Besides giving the explanation of
A particle starts with an initial velocity 2.5m/s along the +ve x axis and it accelerates uniformly at the rate 0.5m/ss. (a) find distance travelled by it in first two seconds. (b)How much time does it take to reach the velocity 7.5m/s (c)How much distance will it cover before reaching the velocity 7.5m/s?, a detailed solution for A particle starts with an initial velocity 2.5m/s along the +ve x axis and it accelerates uniformly at the rate 0.5m/ss. (a) find distance travelled by it in first two seconds. (b)How much time does it take to reach the velocity 7.5m/s (c)How much distance will it cover before reaching the velocity 7.5m/s? has been provided alongside types of A particle starts with an initial velocity 2.5m/s along the +ve x axis and it accelerates uniformly at the rate 0.5m/ss. (a) find distance travelled by it in first two seconds. (b)How much time does it take to reach the velocity 7.5m/s (c)How much distance will it cover before reaching the velocity 7.5m/s? theory, EduRev gives you an
ample number of questions to practice A particle starts with an initial velocity 2.5m/s along the +ve x axis and it accelerates uniformly at the rate 0.5m/ss. (a) find distance travelled by it in first two seconds. (b)How much time does it take to reach the velocity 7.5m/s (c)How much distance will it cover before reaching the velocity 7.5m/s? tests, examples and also practice JEE tests.
|
|
Explore Courses for JEE exam
|
|
Suggested Free Tests
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
|
© EduRev
|
Education Revolution
|
Follow Us
|
Signup to see your scores
go up within 7 days!
Access 1000+ FREE Docs, Videos and Tests
Takes less than 10 seconds to signup