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A rectangular field is twice as long as it is wide. If its area is 2420 m2, what is its perimeter?
  • a)
    110 m
  • b)
    180 m
  • c)
    209 m
  • d)
    240 m
Correct answer is option 'C'. Can you explain this answer?
Most Upvoted Answer
A rectangular field is twice as long as it is wide. If its area is 242...
Understanding the Problem
To solve the problem, we need to determine the dimensions of a rectangular field where the length is twice the width and the area is given as 2420 m².
Step 1: Define Variables
- Let the width of the rectangular field be W meters.
- Then, the length L will be 2W meters (since it is twice as long as it is wide).
Step 2: Area Calculation
- The area A of a rectangle is calculated using the formula:
A = Length × Width
- Substituting the values, we have:
2420 = 2W × W
- This simplifies to:
2420 = 2W²
Step 3: Solve for Width
- Rearranging the equation gives:
W² = 2420 / 2
- Simplifying further:
W² = 1210
- Taking the square root of both sides, we find:
W = √1210 ≈ 34.8 m (rounded to one decimal place)
Step 4: Calculate Length
- Using the width to find the length:
L = 2W = 2 × 34.8 ≈ 69.6 m
Step 5: Calculate the Perimeter
- The perimeter P of a rectangle is calculated using the formula:
P = 2(Length + Width)
- Substituting the values we found:
P = 2(69.6 + 34.8) = 2 × 104.4 = 208.8 m
Since we round to the nearest whole number, the perimeter is approximately 209 m.
Conclusion
The correct answer for the perimeter of the rectangular field is option 'C', which is 209 m.
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Community Answer
A rectangular field is twice as long as it is wide. If its area is 242...
The correct answer is Option C - 209 m
Let the width be w and the length be 2w.
The area is given by length × width = 2w × w = 2w2, and this equals 2420; so 2w2 = 2420.
Thus w2 = 1210, so w = √1210 (take the positive root for a length).
The perimeter is 2(l + w) = 2(2w + w) = 6w, so P = 6√1210.
Numerically, √1210 ≈ 34.785, hence P ≈ 6 × 34.785 = 208.71 m ≈ 209 m
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