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The full-load copper losses and iron losses of a transformer are 6400 W and 5000 Wrespectively. The copper loss and iron loss at half full-load will be respectively.
- a)3200 W and 2500 W
- b)1600 W and 5000 W
- c)3200 W and 5200 W
- d)1600 W and 1250 W
Correct answer is option 'B'. Can you explain this answer?
Most Upvoted Answer
The full-load copper losses and iron losses of a transformer are 6400 ...
Calculation of Copper and Iron Losses
Given,
Full-load copper losses = 6400 W
Iron losses = 5000 W
Let's assume that the transformer has a full load of 1000 W.
Therefore, the total losses in the transformer = Copper losses + Iron losses.
Total losses = 6400 W + 5000 W = 11400 W
Now, if the transformer is loaded at half the full load, i.e. 500 W, then the losses can be calculated as follows:
Copper Losses at Half Full-Load
Copper losses are proportional to the square of the current. Therefore, at half the full-load, the current will be halved, and the copper losses will be reduced to 1/4th of the full-load copper losses.
Copper losses at half full-load = (1/4) x Full-load copper losses
Copper losses at half full-load = (1/4) x 6400 W
Copper losses at half full-load = 1600 W
Iron Losses at Half Full-Load
Iron losses are constant and do not depend on the load. Therefore, the iron losses at half full-load will be the same as the iron losses at full-load.
Iron losses at half full-load = Iron losses at full-load
Iron losses at half full-load = 5000 W
Therefore, the copper loss and iron loss at half full-load will be 1600 W and 5000 W respectively, which is option B.
Given,
Full-load copper losses = 6400 W
Iron losses = 5000 W
Let's assume that the transformer has a full load of 1000 W.
Therefore, the total losses in the transformer = Copper losses + Iron losses.
Total losses = 6400 W + 5000 W = 11400 W
Now, if the transformer is loaded at half the full load, i.e. 500 W, then the losses can be calculated as follows:
Copper Losses at Half Full-Load
Copper losses are proportional to the square of the current. Therefore, at half the full-load, the current will be halved, and the copper losses will be reduced to 1/4th of the full-load copper losses.
Copper losses at half full-load = (1/4) x Full-load copper losses
Copper losses at half full-load = (1/4) x 6400 W
Copper losses at half full-load = 1600 W
Iron Losses at Half Full-Load
Iron losses are constant and do not depend on the load. Therefore, the iron losses at half full-load will be the same as the iron losses at full-load.
Iron losses at half full-load = Iron losses at full-load
Iron losses at half full-load = 5000 W
Therefore, the copper loss and iron loss at half full-load will be 1600 W and 5000 W respectively, which is option B.
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The full-load copper losses and iron losses of a transformer are 6400 ...
Because iron loss is same for all whereas copper loss is in ratio of (1/2,)
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The full-load copper losses and iron losses of a transformer are 6400 W and 5000 Wrespectively. The copper loss and iron loss at half full-load will be respectively.a)3200 W and 2500 Wb)1600 W and 5000 Wc)3200 W and 5200 Wd)1600 W and 1250 WCorrect answer is option 'B'. Can you explain this answer? for Electrical Engineering (EE) 2026 is part of Electrical Engineering (EE) preparation. The Question and answers have been prepared according to the Electrical Engineering (EE) exam syllabus. Information about The full-load copper losses and iron losses of a transformer are 6400 W and 5000 Wrespectively. The copper loss and iron loss at half full-load will be respectively.a)3200 W and 2500 Wb)1600 W and 5000 Wc)3200 W and 5200 Wd)1600 W and 1250 WCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for Electrical Engineering (EE) 2026 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The full-load copper losses and iron losses of a transformer are 6400 W and 5000 Wrespectively. The copper loss and iron loss at half full-load will be respectively.a)3200 W and 2500 Wb)1600 W and 5000 Wc)3200 W and 5200 Wd)1600 W and 1250 WCorrect answer is option 'B'. Can you explain this answer?.
The full-load copper losses and iron losses of a transformer are 6400 W and 5000 Wrespectively. The copper loss and iron loss at half full-load will be respectively.a)3200 W and 2500 Wb)1600 W and 5000 Wc)3200 W and 5200 Wd)1600 W and 1250 WCorrect answer is option 'B'. Can you explain this answer? for Electrical Engineering (EE) 2026 is part of Electrical Engineering (EE) preparation. The Question and answers have been prepared according to the Electrical Engineering (EE) exam syllabus. Information about The full-load copper losses and iron losses of a transformer are 6400 W and 5000 Wrespectively. The copper loss and iron loss at half full-load will be respectively.a)3200 W and 2500 Wb)1600 W and 5000 Wc)3200 W and 5200 Wd)1600 W and 1250 WCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for Electrical Engineering (EE) 2026 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The full-load copper losses and iron losses of a transformer are 6400 W and 5000 Wrespectively. The copper loss and iron loss at half full-load will be respectively.a)3200 W and 2500 Wb)1600 W and 5000 Wc)3200 W and 5200 Wd)1600 W and 1250 WCorrect answer is option 'B'. Can you explain this answer?.
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