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Phenyl isocyanide test is used to identify. a) Aromatic primary amines b) Aromatic secondary amines c) Aromatic tertiary amines d) Quaternary ammonium compounds Correct answer is 'A' . Can you explain this answer.?
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Phenyl isocyanide test is used to identify. a) Aromatic primary amines...
Phenyl Isocyanide Test to Identify Aromatic Primary Amines

The Phenyl Isocyanide Test is a chemical test used to identify the presence of aromatic primary amines. It is based on the reaction of primary aromatic amines with phenyl isocyanide to form a yellow or brown colored complex.

Reaction Mechanism
When a primary aromatic amine is added to phenyl isocyanide, it undergoes a nucleophilic substitution reaction in which the amine group attacks the carbon atom of the isocyanide group. The nitrogen atom of the amine then forms a bond with the carbon atom, and the isocyanide group is converted to an amide group.

The resulting complex is yellow or brown in color and is easily visible. The intensity of the color is directly proportional to the amount of primary aromatic amine present in the sample.

Other Applications
The Phenyl Isocyanide Test is specific to primary aromatic amines and does not react with secondary or tertiary aromatic amines or quaternary ammonium compounds. This test is commonly used in organic chemistry to identify and determine the purity of primary aromatic amines.

In addition to its use in organic chemistry, the Phenyl Isocyanide Test is also used in the pharmaceutical industry to detect impurities in drugs and to determine the concentration of primary aromatic amines in drug formulations.

Conclusion
In conclusion, the Phenyl Isocyanide Test is a simple and effective chemical test used to identify the presence of primary aromatic amines. It is specific to this type of amine and does not react with other types of amines or quaternary ammonium compounds. This test finds its application in organic chemistry and the pharmaceutical industry.
Community Answer
Phenyl isocyanide test is used to identify. a) Aromatic primary amines...
As it is carbylamine reaction in which the primary amine is get converted ibto isocyanide hence the correct option is A.
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Can you explain the answer of this question below:On the basis of aromaticity, there are three types of compounds i.e. aromatic, non-aromatic and antiaromatic.The increasing order of stability of these compounds are is under:Anti-aromatic compound non-aromatic compound aromatic compounds. Compounds to be aromaticfollow the following conditions (according to valence bond theory)(i) The compounds must be be cyclic in structure having (4n + 2) e, where n = Hckels number = 0, 1,2, 3 et.c(ii) The each atoms of the cyclic structure must have unhybridised p-orbital i.e. the atoms of thecompounds have unhybridised p-orbital i.e. usually have sp2 hybrid or planar.(iii) There must be a ring current of electrons in the ring or cyclic structure i.e. cyclic structure mustundergo resonance .Compounds to be anti-aromatic, it must have 4ne where n = 1, 2 and it must be planar and undergoresonance. Non-aromatic compounds the name itself spells that compounds must be non-planarirrespective of number of electrons. Either it has 4ne or (4n + 2) electrons it does not matter.The rate of reaction of any aromatic compounds depends upon the following factors:(i) Electron density(ii) stability of carbocation producedHigher the amount of electron density of the ring, higher will be its rate towards aromatic electrophilicsubstitution and vice-versa. Similarly, higher will be the stability of the produced carbocation after theattack of electrophile, higher will be its rate towards aromatic electrophilic substitution. There is a greateffect of kinetic labelling on the rate of aromatic electrophilic substitution. As we known that higher theatomic weight or, molecualr weight, higher will be the van der Waals force of attraction or, bond energy.Since there will be effect of kienetic labelling if the 2nd step of the reaction will be the slow step, (r.d.s.)otherwise there will be no effect of kinetic labelling.Q. Which of the following is correct order of the rate of reaction of C6H6, C6D6 and C6T6 towardsnitrations?A:C6H6 C6D6 C6T6B:C6H6 = C6D6 = C6T6C:C6H6 C6D6 = C6T6D:C6T6 C6D6 C6H6The answer is b.

On the basis of aromaticity, there are three types of compounds i.e. aromatic, non-aromatic and antiaromatic. The increasing order of stability of these compounds are is under: Anti-aromatic compound < non-aromatic compound < aromatic compounds. Compounds to be aromaticfollow the following conditions (according to valence bond theory)(i) The compounds must be be cyclic in structure having (4n + 2)π e–, where n = Hückel’s number = 0, 1, 2, 3 et.c(ii) The each atoms of the cyclic structure must have unhybridised p-orbital i.e. the atoms of the compounds have unhybridised p-orbital i.e. usually have sp2 hybrid or planar.(iii) There must be a ring current of π electrons in the ring or cyclic structure i.e. cyclic structure mustundergo resonance .Compounds to be anti-aromatic, it must have 4nπe– where n = 1, 2… and it must be planar and undergo resonance. Non-aromatic compounds the name itself spells that compounds must be non-planarirrespective of number of π electrons. Either it has 4nπe– or (4n + 2) π electrons it does not matter.The rate of reaction of any aromatic compounds depends upon the following factors:(i) Electron density(ii) stability of carbocation producedHigher the amount of electron density of the ring, higher will be its rate towards aromatic electrophilic substitution and vice-versa. Similarly, higher will be the stability of the produced carbocation after the attack of electrophile, higher will be its rate towards aromatic electrophilic substitution. There is a great effect of kinetic labelling on the rate of aromatic electrophilic substitution. As we known that higher the atomic weight or, molecualr weight, higher will be the van der Waal’s force of attraction or, bond energy. Since there will be effect of kienetic labelling if the 2nd step of the reaction will be the slow step, (r.d.s.) otherwise there will be no effect of kinetic labelling.Q. Which of the following is correct order of the rate of reaction of C6H6, C6D6 and C6T6 towardssulphonation?

Phenyl isocyanide test is used to identify. a) Aromatic primary amines b) Aromatic secondary amines c) Aromatic tertiary amines d) Quaternary ammonium compounds Correct answer is 'A' . Can you explain this answer.?
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Phenyl isocyanide test is used to identify. a) Aromatic primary amines b) Aromatic secondary amines c) Aromatic tertiary amines d) Quaternary ammonium compounds Correct answer is 'A' . Can you explain this answer.? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about Phenyl isocyanide test is used to identify. a) Aromatic primary amines b) Aromatic secondary amines c) Aromatic tertiary amines d) Quaternary ammonium compounds Correct answer is 'A' . Can you explain this answer.? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Phenyl isocyanide test is used to identify. a) Aromatic primary amines b) Aromatic secondary amines c) Aromatic tertiary amines d) Quaternary ammonium compounds Correct answer is 'A' . Can you explain this answer.?.
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