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If you take a 3-digit number, cycle its digits, and add all three resulting numbers, what is the sum always divisible by?
  • a)
    111
  • b)
    9
  • c)
    37
  • d)
    3
Correct answer is option 'C'. Can you explain this answer?
Most Upvoted Answer
If you take a 3-digit number, cycle its digits, and add all three resu...
The sum of the three numbers formed by cycling the digits of a 3-digit number is always divisible by 37. This occurs because the sum can be expressed as 111(a + b + c), where a, b, and c are the digits, and since 111 is divisible by 37, the entire sum will also be divisible by 37, showcasing interesting properties of number manipulation.
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