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The dimensional formula of coefficient of viscosity is
- a)MLT^-1
- b)[M-1L2T-2]
- c)[ML-1T-1]
- d)Non of these
Correct answer is option 'C'. Can you explain this answer?
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The dimensional formula of coefficient of viscosity isa)MLT^-1b)[M-1L2...
Coefficient of Viscosity Dimensional Formula
Dimensional Formula: [ML^-1T^-1]
Explanation:
Viscosity is defined as the internal frictional force that opposes the motion of the fluid layers relative to each other. The coefficient of viscosity is a measure of the magnitude of this force. The dimensional formula for the coefficient of viscosity can be obtained using the formula for viscosity.
Viscosity = (Force × Distance)/(Area × Velocity)
Dimensional formula for force = [MLT^-2]
Dimensional formula for distance = [L]
Dimensional formula for area = [L^2]
Dimensional formula for velocity = [LT^-1]
Substituting the dimensional formula for these variables in the formula for viscosity, we get:
[ML^-1T^-1] = ([MLT^-2] × [L])/([L^2] × [LT^-1])
Simplifying this expression, we get:
[ML^-1T^-1] = [M^-1L^2T^-2]
Therefore, the dimensional formula for the coefficient of viscosity is [ML^-1T^-1].
Dimensional Formula: [ML^-1T^-1]
Explanation:
Viscosity is defined as the internal frictional force that opposes the motion of the fluid layers relative to each other. The coefficient of viscosity is a measure of the magnitude of this force. The dimensional formula for the coefficient of viscosity can be obtained using the formula for viscosity.
Viscosity = (Force × Distance)/(Area × Velocity)
Dimensional formula for force = [MLT^-2]
Dimensional formula for distance = [L]
Dimensional formula for area = [L^2]
Dimensional formula for velocity = [LT^-1]
Substituting the dimensional formula for these variables in the formula for viscosity, we get:
[ML^-1T^-1] = ([MLT^-2] × [L])/([L^2] × [LT^-1])
Simplifying this expression, we get:
[ML^-1T^-1] = [M^-1L^2T^-2]
Therefore, the dimensional formula for the coefficient of viscosity is [ML^-1T^-1].
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Community Answer
The dimensional formula of coefficient of viscosity isa)MLT^-1b)[M-1L2...
Acc. to the formula - F=6πnrv , n=F/6πrv =[MLT^-2]/[L][LT^-1] Hence the dimensional formula of coefficient of viscosity(n) =[ML^-1T^-1]
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The dimensional formula of coefficient of viscosity isa)MLT^-1b)[M-1L2T-2]c)[ML-1T-1]d)Non of theseCorrect answer is option 'C'. Can you explain this answer?
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