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A stone dropped from a of height h and it reaches after t seconds an earth. From the same building if two stones are thrown(one upwards and another downwards) with the same velocity u and they reach the earth surface after t1 and t2 second respectively, then (a) t= t1-t2 (b) t= [t1+t2]/2 (c) t= [t1t2]2 (D) none of these?
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A stone dropped from a of height h and it reaches after t seconds an e...
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A stone dropped from a of height h and it reaches after t seconds an e...
Explanation:

Given:
- Height of the building: h
- Time taken for the stone to reach the Earth when dropped: t
- Velocity of the stones thrown upwards and downwards: u
- Time taken for the stone thrown upwards to reach the Earth: t1
- Time taken for the stone thrown downwards to reach the Earth: t2

Analysis:
1. When the stone is dropped from a height h, it falls freely under the influence of gravity.
2. The time taken for the stone to reach the Earth is given by the equation: h = (1/2)gt^2, where g is the acceleration due to gravity.
3. Solving for t, we get t = sqrt(2h/g).

Analysis of the stones thrown upwards and downwards:
1. When the stone is thrown upwards with a velocity u, it will rise to a certain height and then fall back to the Earth.
2. The time taken for the stone to reach the Earth when thrown upwards is given by the equation: h = ut1 - (1/2)gt1^2.
3. Rearranging the equation, we get (1/2)gt1^2 - ut1 + h = 0.
4. Similarly, when the stone is thrown downwards with a velocity u, it will fall towards the Earth.
5. The time taken for the stone to reach the Earth when thrown downwards is given by the equation: h = ut2 + (1/2)gt2^2.
6. Rearranging the equation, we get (1/2)gt2^2 + ut2 - h = 0.
7. Solving both equations using the quadratic formula, we get:
- t1 = (u + sqrt(u^2 + 2gh))/g
- t2 = (u - sqrt(u^2 + 2gh))/g

Conclusion:
1. Comparing the equations for t, t1, and t2, we can see that none of the given options (a), (b), or (c) are correct.
2. Therefore, the correct answer is (D) none of these.
3. The time taken for the stone dropped from a height h to reach the Earth is not equal to the difference or average of the times taken for the stones thrown upwards and downwards to reach the Earth.
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A stone dropped from a of height h and it reaches after t seconds an earth. From the same building if two stones are thrown(one upwards and another downwards) with the same velocity u and they reach the earth surface after t1 and t2 second respectively, then (a) t= t1-t2 (b) t= [t1+t2]/2 (c) t= [t1t2]2 (D) none of these?
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A stone dropped from a of height h and it reaches after t seconds an earth. From the same building if two stones are thrown(one upwards and another downwards) with the same velocity u and they reach the earth surface after t1 and t2 second respectively, then (a) t= t1-t2 (b) t= [t1+t2]/2 (c) t= [t1t2]2 (D) none of these? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about A stone dropped from a of height h and it reaches after t seconds an earth. From the same building if two stones are thrown(one upwards and another downwards) with the same velocity u and they reach the earth surface after t1 and t2 second respectively, then (a) t= t1-t2 (b) t= [t1+t2]/2 (c) t= [t1t2]2 (D) none of these? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A stone dropped from a of height h and it reaches after t seconds an earth. From the same building if two stones are thrown(one upwards and another downwards) with the same velocity u and they reach the earth surface after t1 and t2 second respectively, then (a) t= t1-t2 (b) t= [t1+t2]/2 (c) t= [t1t2]2 (D) none of these?.
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