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The remainder when 2xcube-xsquare +3x-2 is divided by 2x-1 is. a) 1/2 b) -1/2 c) -3/2 d) z?
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The remainder when 2xcube-xsquare +3x-2 is divided by 2x-1 is. a) 1/2 ...
Given:
The expression is 2x^3 - x^2 + 3x - 2.

To Find:
The remainder when the expression is divided by 2x - 1.

Solution:
We can use polynomial long division to find the remainder when the given expression is divided by 2x - 1.

Step 1: Divide the first term of the expression (2x^3) by the first term of the divisor (2x). The quotient is x^2.

Step 2: Multiply the divisor (2x - 1) by the quotient (x^2). The result is (2x^3 - x^2).

Step 3: Subtract the product from the original expression.
(2x^3 - x^2 + 3x - 2) - (2x^3 - x^2) = 3x - 2.

Step 4: Repeat the process with the new expression (3x - 2).
Divide the first term (3x) by the first term of the divisor (2x). The quotient is (3/2).

Step 5: Multiply the divisor (2x - 1) by the new quotient (3/2). The result is (3x - 3/2).

Step 6: Subtract the product from the new expression.
(3x - 2) - (3x - 3/2) = -2 + 3/2 = -1/2.

Step 7: The remainder is -1/2.

Answer:
So, the remainder when 2x^3 - x^2 + 3x - 2 is divided by 2x - 1 is -1/2. Therefore, option (b) -1/2 is the correct answer.
Community Answer
The remainder when 2xcube-xsquare +3x-2 is divided by 2x-1 is. a) 1/2 ...
Answer is b
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