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A simple pendulum of length 5m with a bob of mass 1 kg, is in simple harmonicmotion. As it passes through its mean position, the bob has a speed of 5m/s. The net force on the bob at the mean position is:-
  • a)
    Zero
  • b)
    2.5 N
  • c)
    5N
  • d)
    25N
Correct answer is option 'A'. Can you explain this answer?
Most Upvoted Answer
A simple pendulum of length 5m with a bob of mass 1 kg, is in simple h...
Explanation:

  • Given, length of the pendulum, l = 5m

  • Mass of the bob, m = 1 kg

  • Speed of the bob at mean position, v = 5m/s

  • At the mean position, the displacement of the bob is zero and hence the net force on the bob is zero as well.

  • At the mean position, the gravitational force acting downward on the bob is balanced by the tension force acting upward on the string.

  • As the bob is in simple harmonic motion, the net force acting on the bob at any point is given by F = -kx, where F is the net force, k is the spring constant and x is the displacement from the mean position.

  • However, in the case of a pendulum, the restoring force is provided by the weight of the bob and not a spring. The restoring force is given by F = -mg sinθ, where θ is the angle made by the string with the vertical.

  • At the mean position, sinθ = 0 and hence the restoring force is zero. Therefore, the net force on the bob at the mean position is zero.

  • Hence, option A is the correct answer.

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Community Answer
A simple pendulum of length 5m with a bob of mass 1 kg, is in simple h...
The net force is causing the Bob to move in a circle----- As we know that the bob's velocity is 5m/s and it is performing a circular(arc) motion with the radius 5m-----for this to happen, Bob must expirence a force of mv²/r to perform circular motion----- (1kg * (5m/s)²)/5 = 5N----- Tension on the string-weight of the Bob = mv²/r -----Correct answer is C.
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A simple pendulum of length 5m with a bob of mass 1 kg, is in simple harmonicmotion. As it passes through its mean position, the bob has a speed of 5m/s. The net force on the bob at the mean position is:-a)Zerob)2.5 Nc) 5Nd)25NCorrect answer is option 'A'. Can you explain this answer?
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