The magnetic field inside a toroidal solenoid of radius R is B. If the...
The magnetic field inside a toroidal solenoid is given by the equation:
B = μ₀nI
Where:
- B is the magnetic field
- μ₀ is the permeability of free space
- n is the number of turns per unit length
- I is the current
Now, let's consider the scenario where the current through the solenoid is doubled and the radius is also doubled, while keeping the number of turns per unit length the same.
1. Magnetic field inside the original solenoid:
Given that the magnetic field inside the original solenoid is B, we can write:
B₁ = μ₀nI
2. Magnetic field inside the new solenoid:
Since the current is doubled and the radius is doubled, the new current is 2I and the new radius is 2R. The number of turns per unit length remains the same, so n remains unchanged.
Using the same equation as before, we can calculate the new magnetic field:
B₂ = μ₀n(2I)
Simplifying this equation, we get:
B₂ = 2(μ₀nI)
Comparing B₁ and B₂, we can see that B₂ is twice the value of B₁. Therefore, the magnetic field produced by the new solenoid is twice the magnetic field produced by the original solenoid.
So, the correct answer is option 'D': 2B.
The magnetic field inside a toroidal solenoid of radius R is B. If the...
As B = uo n I then B' = uo n 2I B'/2 = B I.e., B' = 2B