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Factorise 2x^3-xy^2_y^3?
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Factorise 2x^3-xy^2_y^3?
Let    P(x)  =  2 x^3 - x y^2 - y^3
We see that if x = y, then P(x=y) = 0.   
Then by Remainder and factor theorem, (x - y) is a factor.

let   P(x) = (x - y) [ 2 x^2 - a x y + y^2 ]
=  2 x^3 - a x^2 y + x y^2 - 2 x^2 y + a x y^2 - y^3
= 2 x^3 - (a+2) x^2 y + (a+1) x y^2 - y^3

By comparing coefficients:  a= -2

P(x) = ( x - y) [2 x^2 + 2 x y + y^2]
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Factorise 2x^3-xy^2_y^3?
Factorising 2x^3 - xy^2 - y^3
To factorise the expression 2x^3 - xy^2 - y^3, we need to look for common factors among the terms. The first step is to identify any common variables present in all the terms.

Step 1: Identify common variables
In this expression, the common variable is y. We can factor out a y from all the terms:
2x^3 - xy^2 - y^3 = y(2x^3 - x*y - y^2)

Step 2: Factorise the remaining expression
Now, we need to factorise the expression inside the parentheses: 2x^3 - x*y - y^2.
This expression can be factored by grouping the terms:
2x^3 - x*y - y^2 = 2x^2(x - y) - y(x - y) = (2x^2 - y)(x - y)

Step 3: Combine the factors
Now, we can combine the factors from step 1 and step 2 to get the final factorised form of the expression:
2x^3 - xy^2 - y^3 = y(2x^2 - y)(x - y)
Therefore, the factorised form of 2x^3 - xy^2 - y^3 is y(2x^2 - y)(x - y).
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