Calculation of number of oxygen atoms in 10.6 gm of Na2CO3
- First, calculate the molar mass of Na2CO3:
- The molar mass of Na2CO3 = 2(Na) + 1(C) + 3(O) = 2(23) + 12 + 3(16) = 106 g/mol
- Next, calculate the number of moles of Na2CO3 in 10.6 gm:
- Number of moles = given mass / molar mass = 10.6 / 106 = 0.1 mol
- Now, determine the number of moles of oxygen atoms in Na2CO3:
- In Na2CO3, there are 3 oxygen atoms per molecule
- Number of moles of oxygen atoms = 0.1 mol * 3 = 0.3 mol
- Finally, calculate the number of oxygen atoms present:
- Avogadro's number states that 1 mol of any substance contains 6.022 x 10^23 particles
- Number of oxygen atoms = number of moles * Avogadro's number = 0.3 * 6.022 x 10^23 = 1.8066 x 10^23 atoms
Therefore, there are approximately 1.81 x 10^23 oxygen atoms present in 10.6 gm of Na2CO3.

18.066×10^22