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No of atoms of oxygen present in 10.6 gm of Na2CO3 will be?
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No of atoms of oxygen present in 10.6 gm of Na2CO3 will be?
Calculation of number of oxygen atoms in 10.6 gm of Na2CO3
- First, calculate the molar mass of Na2CO3:
- The molar mass of Na2CO3 = 2(Na) + 1(C) + 3(O) = 2(23) + 12 + 3(16) = 106 g/mol
- Next, calculate the number of moles of Na2CO3 in 10.6 gm:
- Number of moles = given mass / molar mass = 10.6 / 106 = 0.1 mol
- Now, determine the number of moles of oxygen atoms in Na2CO3:
- In Na2CO3, there are 3 oxygen atoms per molecule
- Number of moles of oxygen atoms = 0.1 mol * 3 = 0.3 mol
- Finally, calculate the number of oxygen atoms present:
- Avogadro's number states that 1 mol of any substance contains 6.022 x 10^23 particles
- Number of oxygen atoms = number of moles * Avogadro's number = 0.3 * 6.022 x 10^23 = 1.8066 x 10^23 atoms
Therefore, there are approximately 1.81 x 10^23 oxygen atoms present in 10.6 gm of Na2CO3.
- First, calculate the molar mass of Na2CO3:
- The molar mass of Na2CO3 = 2(Na) + 1(C) + 3(O) = 2(23) + 12 + 3(16) = 106 g/mol
- Next, calculate the number of moles of Na2CO3 in 10.6 gm:
- Number of moles = given mass / molar mass = 10.6 / 106 = 0.1 mol
- Now, determine the number of moles of oxygen atoms in Na2CO3:
- In Na2CO3, there are 3 oxygen atoms per molecule
- Number of moles of oxygen atoms = 0.1 mol * 3 = 0.3 mol
- Finally, calculate the number of oxygen atoms present:
- Avogadro's number states that 1 mol of any substance contains 6.022 x 10^23 particles
- Number of oxygen atoms = number of moles * Avogadro's number = 0.3 * 6.022 x 10^23 = 1.8066 x 10^23 atoms
Therefore, there are approximately 1.81 x 10^23 oxygen atoms present in 10.6 gm of Na2CO3.
Community Answer
No of atoms of oxygen present in 10.6 gm of Na2CO3 will be?
18.066×10^22
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No of atoms of oxygen present in 10.6 gm of Na2CO3 will be?
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No of atoms of oxygen present in 10.6 gm of Na2CO3 will be? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about No of atoms of oxygen present in 10.6 gm of Na2CO3 will be? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for No of atoms of oxygen present in 10.6 gm of Na2CO3 will be?.
No of atoms of oxygen present in 10.6 gm of Na2CO3 will be? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about No of atoms of oxygen present in 10.6 gm of Na2CO3 will be? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for No of atoms of oxygen present in 10.6 gm of Na2CO3 will be?.
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