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A stone thrown from the top of a building is given an initial velocity of 20.0 m/s straight upward. Determine the time in seconds at which the stone reaches its maximum height.
g =9.8 m / sec2
  • a)
    1.67
  • b)
    2.8
  • c)
    2.7
  • d)
    2.04
Correct answer is option 'D'. Can you explain this answer?
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A stone thrown from the top of a building is given an initial velocity...
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A stone thrown from the top of a building is given an initial velocity...
Given:
Initial velocity, u = 20.0 m/s (upward)
Acceleration due to gravity, g = 9.8 m/s²

To find:
Time taken by the stone to reach its maximum height.

Solution:
When a stone is thrown upwards, it will initially move upwards against the force of gravity until its velocity becomes zero. After that, it will start falling downwards due to the force of gravity.

At the maximum height, the velocity of the stone becomes zero. Therefore, we can use the equation of motion to find the time taken by the stone to reach its maximum height.

Final velocity, v = 0 m/s (at maximum height)
Acceleration, a = g = 9.8 m/s²
Initial velocity, u = 20.0 m/s (upward)

Using the equation of motion:
v = u + at

We get:
0 = 20.0 - 9.8t

Solving for t, we get:
t = 20.0/9.8
t ≈ 2.04 seconds

Therefore, the time taken by the stone to reach its maximum height is 2.04 seconds.

Answer: Option D.
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A stone thrown from the top of a building is given an initial velocity...
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A stone thrown from the top of a building is given an initial velocity of 20.0 m/s straight upward. Determine the time in seconds at which the stone reaches its maximum height.g =9.8 m / sec2a)1.67b)2.8c)2.7d)2.04Correct answer is option 'D'. Can you explain this answer?
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