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If the two voltage measurements are V1= 150+_2% and V2=100+_4% respectively. Then the maximum percentage errors in the sum of two voltage measurement is. 1)+_ 2.4% 2) +_2.6% 3) +_2.8% 4) +_3.4%?
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If the two voltage measurements are V1= 150+_2% and V2=100+_4% respect...
Solution:

Given, V1 = 150 ± 2% and V2 = 100 ± 4%

To find the maximum percentage error in the sum of two voltage measurements, we need to first find the individual percentage errors in V1 and V2.

Percentage error in V1 = (2/100) x 100% = 2%

Percentage error in V2 = (4/100) x 100% = 4%

Now, we can use the formula for percentage error in the sum of two quantities:

Percentage error in (V1 + V2) = [(Percentage error in V1)2 + (Percentage error in V2)2]1/2

= [(2%)2 + (4%)2]1/2

= (4 + 16)1/2 %

= (20)1/2 %

= 4.47%

Therefore, the maximum percentage error in the sum of two voltage measurements is 4.47%, which is closest to option (4) _3.4%.

Answer: 4) _3.4%
Community Answer
If the two voltage measurements are V1= 150+_2% and V2=100+_4% respect...
(3) +_2.8%
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If the two voltage measurements are V1= 150+_2% and V2=100+_4% respectively. Then the maximum percentage errors in the sum of two voltage measurement is. 1)+_ 2.4% 2) +_2.6% 3) +_2.8% 4) +_3.4%?
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