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A 25 bulb emit monochromatic yellow light of wavelength of 0.57um what is the rate of emission of quanta per second ?
Verified Answer
A 25 bulb emit monochromatic yellow light of wavelength of 0.57um what...
Power = 25 Watts  = 25 Joules /second
λ = 0.57 μm
energy in a photon = h c / λ 

Power = n * h c / λ         
where n  = number of photons quanta emitted per second
=>    25 =  n * 6.626 * 10⁻3⁴ * 2.98 * 10⁸ /0.57 * 10⁻⁶ 
 => n =  7.218 * 101⁹  per second 

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Most Upvoted Answer
A 25 bulb emit monochromatic yellow light of wavelength of 0.57um what...
Power of bulb, P = 25 Watt = 25 Js^–1 Energy of one photon, E = hν  =hc/ lambda Substituting the values in the of E: E=(6.626×10^34)(3×10^8)/0.57×10^-6 E = 34.87 × 10^–20 J emission of quanta per second =>25/34.87×10^-20 =7.169×10^19 s^-1
Community Answer
A 25 bulb emit monochromatic yellow light of wavelength of 0.57um what...
Calculation of Rate of Emission of Quanta per Second
- Given:
- Number of bulbs (N) = 25
- Wavelength of light (λ) = 0.57 μm
- Speed of light (c) = 3 x 10^8 m/s
- Planck's constant (h) = 6.63 x 10^-34 J.s

Step 1: Calculate the Frequency of the Yellow Light
The speed of light formula c = λν can be rearranged to find the frequency (ν) of the yellow light.
ν = c / λ
ν = (3 x 10^8 m/s) / (0.57 x 10^-6 m)
ν ≈ 5.26 x 10^14 Hz

Step 2: Calculate the Energy of a Photon
The energy of a photon formula E = hν can be used to find the energy of a single photon of the yellow light.
E = (6.63 x 10^-34 J.s) x (5.26 x 10^14 Hz)
E ≈ 3.49 x 10^-19 J

Step 3: Calculate the Rate of Emission of Quanta per Second
The rate of emission of quanta per second is given by the formula:
Rate = N x E x ν
Rate = 25 x 3.49 x 10^-19 J x 5.26 x 10^14 Hz
Rate ≈ 4.34 x 10^17 quanta per second
Therefore, the rate of emission of quanta per second from 25 bulbs emitting monochromatic yellow light with a wavelength of 0.57 μm is approximately 4.34 x 10^17 quanta per second.
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A 25 bulb emit monochromatic yellow light of wavelength of 0.57um what is the rate of emission of quanta per second ?
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