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Find slope of normal to the curve y=5x2-10x + 7 at x=1
- a)not defined
- b)-1
- c)1
- d)zero
Correct answer is option 'A'. Can you explain this answer?
Verified Answer
Find slope of normal to the curve y=5x2-10x + 7 at x=1a)not def...
y = 5x2 - 10x + 7
dy/dx = 10x - 10
(At x = 1) 10(1) - 10
m1 = 0
As we know that slope, m1m2 = -1
=> 0(m2) = -1
m2 = -1/0 (which is not defined)
dy/dx = 10x - 10
(At x = 1) 10(1) - 10
m1 = 0
As we know that slope, m1m2 = -1
=> 0(m2) = -1
m2 = -1/0 (which is not defined)
Most Upvoted Answer
Find slope of normal to the curve y=5x2-10x + 7 at x=1a)not def...
For :- slope of normal = m1*m2=-1 Then, take the derivative of f(x) means derivative of y according to question So it will be, F(x) = 5x2-10x+7 F'(x) =10x-10 Then put the value of x in f'(x) It vil be 10(1)-10=0 So always remember tht the answer u got after putting the value of is m1 Now, Put in the formula 0*m2=-1 m2=-1/0 As u no tht 1/0 is not defined So answer is (a)...
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Find slope of normal to the curve y=5x2-10x + 7 at x=1a)not def...
y = 5x2 - 10x + 7
dy/dx = 10x - 10
(At x = 1) 10(1) - 10
m1 = 0
As we know that slope, m1m2 = -1
=> 0(m2) = -1
m2 = -1/0 (which is not defined)
dy/dx = 10x - 10
(At x = 1) 10(1) - 10
m1 = 0
As we know that slope, m1m2 = -1
=> 0(m2) = -1
m2 = -1/0 (which is not defined)
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