All Courses
Get the App Signup / Login
Sign in Open App
JEE Question  >  Differentiate sin2(θ2 + 1) with respect ... Save

Related Test
Differentiate sin2(θ2 + 1) with respect to θ2
  • a)
    sin(2θ2 + 1)
  • b)
    cos(2θ2 + 2)
  • c)
    sin(2θ2 + 2)
  • d)
    cos(2θ2 + 1)
Correct answer is option 'C'. Can you explain this answer?

Answers

First u just differentiate sin^2(ø^2+1) with respect to sin(ø^2+1) so we get 2sin(ø^2+1)..Then again differentiate sin(ø^2+1) with respect to (ø^2+1) so we get cos(ø^2+1). and now lastly we differentiate (ø^2+1) with respect to ø^2 so we get 1 ..... and lastly the result is 2sin(ø^2+1)×cos(ø^2+1)×1 = sin2(ø^2+1) = sin(2ø^2+2)..... Here , ø= theta ....

1 Crore+ students have signed up on EduRev. Have you?
Differentiate sin2(θ2 + 1) with respect toθ2a)sin(2θ2 + 1)b)cos(2θ2 + 2)c)sin(2θ2 + 2)d)cos(2θ2 + 1)Correct answer is option 'C'. Can you explain this answer?

View courses related to this question
Explore JEE courses
Explore JEE courses
View courses related to this question
Share with a friend
Answer this doubt

Similar JEE Doubts

Question Description
Differentiate sin2(θ2 + 1) with respect toθ2a)sin(2θ2 + 1)b)cos(2θ2 + 2)c)sin(2θ2 + 2)d)cos(2θ2 + 1)Correct answer is option 'C'. Can you explain this answer? for JEE 2023 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about Differentiate sin2(θ2 + 1) with respect toθ2a)sin(2θ2 + 1)b)cos(2θ2 + 2)c)sin(2θ2 + 2)d)cos(2θ2 + 1)Correct answer is option 'C'. Can you explain this answer? covers all topics & solutions for JEE 2023 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Differentiate sin2(θ2 + 1) with respect toθ2a)sin(2θ2 + 1)b)cos(2θ2 + 2)c)sin(2θ2 + 2)d)cos(2θ2 + 1)Correct answer is option 'C'. Can you explain this answer?.
Solutions for Differentiate sin2(θ2 + 1) with respect toθ2a)sin(2θ2 + 1)b)cos(2θ2 + 2)c)sin(2θ2 + 2)d)cos(2θ2 + 1)Correct answer is option 'C'. Can you explain this answer? in English & in Hindi are available as part of our courses for JEE. Download more important topics, notes, lectures and mock test series for JEE Exam by signing up for free.
Here you can find the meaning of Differentiate sin2(θ2 + 1) with respect toθ2a)sin(2θ2 + 1)b)cos(2θ2 + 2)c)sin(2θ2 + 2)d)cos(2θ2 + 1)Correct answer is option 'C'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of Differentiate sin2(θ2 + 1) with respect toθ2a)sin(2θ2 + 1)b)cos(2θ2 + 2)c)sin(2θ2 + 2)d)cos(2θ2 + 1)Correct answer is option 'C'. Can you explain this answer?, a detailed solution for Differentiate sin2(θ2 + 1) with respect toθ2a)sin(2θ2 + 1)b)cos(2θ2 + 2)c)sin(2θ2 + 2)d)cos(2θ2 + 1)Correct answer is option 'C'. Can you explain this answer? has been provided alongside types of Differentiate sin2(θ2 + 1) with respect toθ2a)sin(2θ2 + 1)b)cos(2θ2 + 2)c)sin(2θ2 + 2)d)cos(2θ2 + 1)Correct answer is option 'C'. Can you explain this answer? theory, EduRev gives you an ample number of questions to practice Differentiate sin2(θ2 + 1) with respect toθ2a)sin(2θ2 + 1)b)cos(2θ2 + 2)c)sin(2θ2 + 2)d)cos(2θ2 + 1)Correct answer is option 'C'. Can you explain this answer? tests, examples and also practice JEE tests.

Related JEE Content

Top Courses for JEE

Physics For JEE
Chemistry for JEE
Mathematics For JEE
Physics 35 Years JEE Main & Advanced Past year Papers
Chemistry 35 Years JEE Main & Advanced Past year Papers

Download free EduRev App

Track your progress, build streaks, highlight & save important lessons and more!
(Scan QR code)
First u just differentiate sin^2(ø^2+1) with respect to sin(ø^2+1) so we get 2sin(ø^2+1)..Then again differentiate sin(ø^2+1) with respect to (ø^2+1) so we get cos(ø^2+1). and now lastly we differentiate (ø^2+1) with respect to ø^2 so we get 1 ..... and lastly the result is 2sin(ø^2+1)×cos(ø^2+1)×1 = sin2(ø^2+1) = sin(2ø^2+2)..... Here , ø= theta ....
Get App
© EduRev
Education Revolution
Follow Us