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Differentiate sin22 + 1) with respect to θ2
  • a)
    sin(2θ2 + 1)
  • b)
    cos(2θ2 + 2)
  • c)
    sin(2θ2 + 2)
  • d)
    cos(2θ2 + 1)
Correct answer is option 'C'. Can you explain this answer?

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Sonålí Raåz
Jul 23, 2018
Related Differentiate sin2(θ2 + 1) with respect toθ2a)sin(2θ2 + 1)b)cos(2θ2 + 2)c)sin(2θ2 + 2)d)cos(2θ2 + 1)Correct answer is option 'C'. Can you explain this answer?
First u just differentiate sin^2(ø^2+1) with respect to sin(ø^2+1) so we get 2sin(ø^2+1)..Then again differentiate sin(ø^2+1) with respect to (ø^2+1) so we get cos(ø^2+1). and now lastly we differentiate (ø^2+1) with respect to ø^2 so we get 1 ..... and lastly the result is 2sin(ø^2+1)×cos(ø^2+1)×1 = sin2(ø^2+1) = sin(2ø^2+2)..... Here , ø= theta ....

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Differentiate sin2(θ2 + 1) with respect toθ2a)sin(2θ2 + 1)b)cos(2θ2 + 2)c)sin(2θ2 + 2)d)cos(2θ2 + 1)Correct answer is option 'C'. Can you explain this answer? for JEE 2022 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about Differentiate sin2(θ2 + 1) with respect toθ2a)sin(2θ2 + 1)b)cos(2θ2 + 2)c)sin(2θ2 + 2)d)cos(2θ2 + 1)Correct answer is option 'C'. Can you explain this answer? covers all topics & solutions for JEE 2022 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Differentiate sin2(θ2 + 1) with respect toθ2a)sin(2θ2 + 1)b)cos(2θ2 + 2)c)sin(2θ2 + 2)d)cos(2θ2 + 1)Correct answer is option 'C'. Can you explain this answer?.
Solutions for Differentiate sin2(θ2 + 1) with respect toθ2a)sin(2θ2 + 1)b)cos(2θ2 + 2)c)sin(2θ2 + 2)d)cos(2θ2 + 1)Correct answer is option 'C'. Can you explain this answer? in English & in Hindi are available as part of our courses for JEE. Download more important topics, notes, lectures and mock test series for JEE Exam by signing up for free.
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First u just differentiate sin^2(ø^2+1) with respect to sin(ø^2+1) so we get 2sin(ø^2+1)..Then again differentiate sin(ø^2+1) with respect to (ø^2+1) so we get cos(ø^2+1). and now lastly we differentiate (ø^2+1) with respect to ø^2 so we get 1 ..... and lastly the result is 2sin(ø^2+1)×cos(ø^2+1)×1 = sin2(ø^2+1) = sin(2ø^2+2)..... Here , ø= theta ....