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A solenoid coil of 300 turns /m is carrying a current of 5 A. Calculate the magnitude of magnetic intensity inside the solenoid.​
  • a)
    1.9 T
  • b)
    1.9 X 10-6 T
  • c)
    1.9 X 10-3 T
  • d)
    1.9 X 10-7 T
Correct answer is option 'C'. Can you explain this answer?
Most Upvoted Answer
A solenoid coil of 300 turns /m is carrying a current of 5 A. Calculat...
We know, Magnetic field of solenoid,
= μonI
=4πx10-7x300x5
=4πx15x10-5
=6πx10-9
=18.89x10-9
≈1.9x10-3T
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A solenoid coil of 300 turns /m is carrying a current of 5 A. Calculat...
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A solenoid coil of 300 turns /m is carrying a current of 5 A. Calculate the magnitude of magnetic intensity inside the solenoid.​a)1.9 Tb)1.9 X 10-6Tc)1.9 X 10-3Td)1.9 X 10-7TCorrect answer is option 'C'. Can you explain this answer? for Class 12 2025 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about A solenoid coil of 300 turns /m is carrying a current of 5 A. Calculate the magnitude of magnetic intensity inside the solenoid.​a)1.9 Tb)1.9 X 10-6Tc)1.9 X 10-3Td)1.9 X 10-7TCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for Class 12 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A solenoid coil of 300 turns /m is carrying a current of 5 A. Calculate the magnitude of magnetic intensity inside the solenoid.​a)1.9 Tb)1.9 X 10-6Tc)1.9 X 10-3Td)1.9 X 10-7TCorrect answer is option 'C'. Can you explain this answer?.
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