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The equation of a line whose perpendicular distance from the origin is 3 units and the angle made by perpendicular with positive x-axis is 30° is:a)x +√3y = 16b)x +√3y = 6c)√3x + y +6= 0d)√3x + y -2 = 0Correct answer is option 'D'. Can you explain this answer? for JEE 2026 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about The equation of a line whose perpendicular distance from the origin is 3 units and the angle made by perpendicular with positive x-axis is 30° is:a)x +√3y = 16b)x +√3y = 6c)√3x + y +6= 0d)√3x + y -2 = 0Correct answer is option 'D'. Can you explain this answer? covers all topics & solutions for JEE 2026 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The equation of a line whose perpendicular distance from the origin is 3 units and the angle made by perpendicular with positive x-axis is 30° is:a)x +√3y = 16b)x +√3y = 6c)√3x + y +6= 0d)√3x + y -2 = 0Correct answer is option 'D'. Can you explain this answer?.

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