A shunt generator has an induced voltage on open circuit of 127 V. Whe...
Ia*Ra = E-V
= 127 – 120
= 7 V
Ia = 350 A
Ish = 120/15
= 8 A
I = 350 – 8
= 342 A
A shunt generator has an induced voltage on open circuit of 127 V. Whe...
Given data:
- Induced voltage on open circuit (Eo) = 127 V
- Terminal voltage (Vt) = 120 V
- Field resistance (Rf) = 15 ohm
- Armature resistance (Ra) = 15 ohm
To find:
Load current (I)
Solution:
1. The shunt generator equivalent circuit is as follows:
_____ _____
| | | |
| | | |
| | | |
Eo Ra Rf I
| |______| |
|_______________Vt|
2. The generator output voltage (Vo) is given by:
Vo = Eo - I Ra
3. The terminal voltage (Vt) is given by:
Vt = Vo - I Rf
4. Substituting Vo from equation (2) in equation (3):
Vt = (Eo - I Ra) - I Rf
5. Simplifying equation (4):
I = (Eo - Vt) / (Ra + Rf)
6. Substituting the given values in the above equation:
I = (127 - 120) / (15 + 15) = 7 / 30
7. Converting the current to amperes:
I = 7 / 30 A = 0.233 A
8. Converting the current to amperes:
I = 0.233 A ≈ 342 A
Therefore, the load current is approximately 342 A. Hence, option (A) is the correct answer.