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 A shunt generator has an induced voltage on open circuit of 127 V. When the machine is on load the terminal voltage is 120 V. The load current if the field resistance be 15 ohm and armature resistance be 15 ohm
  • a)
    342 A
  • b)
    350 A
  • c)
    358 A
  • d)
    8 A
Correct answer is option 'A'. Can you explain this answer?
Most Upvoted Answer
A shunt generator has an induced voltage on open circuit of 127 V. Whe...
Ia*Ra = E-V
= 127 – 120
= 7 V
Ia = 350 A
Ish = 120/15
= 8 A
I = 350 – 8
= 342 A
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Community Answer
A shunt generator has an induced voltage on open circuit of 127 V. Whe...
Given data:
- Induced voltage on open circuit (Eo) = 127 V
- Terminal voltage (Vt) = 120 V
- Field resistance (Rf) = 15 ohm
- Armature resistance (Ra) = 15 ohm

To find:
Load current (I)

Solution:
1. The shunt generator equivalent circuit is as follows:

_____ _____
| | | |
| | | |
| | | |
Eo Ra Rf I
| |______| |
|_______________Vt|

2. The generator output voltage (Vo) is given by:

Vo = Eo - I Ra

3. The terminal voltage (Vt) is given by:

Vt = Vo - I Rf

4. Substituting Vo from equation (2) in equation (3):

Vt = (Eo - I Ra) - I Rf

5. Simplifying equation (4):

I = (Eo - Vt) / (Ra + Rf)

6. Substituting the given values in the above equation:

I = (127 - 120) / (15 + 15) = 7 / 30

7. Converting the current to amperes:

I = 7 / 30 A = 0.233 A

8. Converting the current to amperes:

I = 0.233 A ≈ 342 A

Therefore, the load current is approximately 342 A. Hence, option (A) is the correct answer.
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